4-3.18. Repeat Prob. 4-3.17 if the loads Q are zero and each load P = 2000 lb.
4-3.18. Repeat Prob. 4-3.17 if the loads Q are zero and each load P = 2000 lb.
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Chapter10: Statically Indeterminate Beams
Section: Chapter Questions
Problem 10.4.8P: The continuous frame ABC has a pin support at /l, roller supports at B and C, and a rigid corner...
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Question
Solve problem 4-3.18, if the loads Q are zero and each P = 2000 lb
Also solve, P-4-3.19, if each load P = 1500 lb and each load Q = 2500 lb
![4-4 Method of Sections
125
4-3.17. Find the force in members AB, AC, BC, BID, CD, and CE for
the truss shown in Fig. P-4-3.17. Assume that the loads P are zero and
that each load () = 4000 1lb.
%3D
BD = 5660 lb C; CE = 6940 lb T
%3D
%3D
4-3.18. Repeat Prob. 4-3.17 if the loads Q are zero and each load
P = 2000 lb.
%3D
4-3.19. Repeat Prob. 4-3.17 if each load P = 1500 lb and each load
Q = 2500 lb.
%3D
BD = 4440 lb C; CE = 5065 lb T
%3D
4-4 METHOD OF SECTIONS
We have seen that the method of joints consists of analyzing trusses
the principles of equilibrium to the concurrent force
of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F341807b9-90a5-4a92-b9fb-2fed63cc27c4%2F20cbd5df-75b4-4ff4-a89a-b0bf4710ec21%2Fv0g3esh.jpeg&w=3840&q=75)
Transcribed Image Text:4-4 Method of Sections
125
4-3.17. Find the force in members AB, AC, BC, BID, CD, and CE for
the truss shown in Fig. P-4-3.17. Assume that the loads P are zero and
that each load () = 4000 1lb.
%3D
BD = 5660 lb C; CE = 6940 lb T
%3D
%3D
4-3.18. Repeat Prob. 4-3.17 if the loads Q are zero and each load
P = 2000 lb.
%3D
4-3.19. Repeat Prob. 4-3.17 if each load P = 1500 lb and each load
Q = 2500 lb.
%3D
BD = 4440 lb C; CE = 5065 lb T
%3D
4-4 METHOD OF SECTIONS
We have seen that the method of joints consists of analyzing trusses
the principles of equilibrium to the concurrent force
of
![Figure P-4-3.17
45°
09
.09
09
.09
09
75°
75°
09
H.
B.
09
D.
P.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F341807b9-90a5-4a92-b9fb-2fed63cc27c4%2F20cbd5df-75b4-4ff4-a89a-b0bf4710ec21%2F0zo3b2f.jpeg&w=3840&q=75)
Transcribed Image Text:Figure P-4-3.17
45°
09
.09
09
.09
09
75°
75°
09
H.
B.
09
D.
P.
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