3. The following molar concentrations were obtained from replicate standardization of a solution: 0.5026, 0.5029, 0.5023, 0.5031, 0.5025, 0.5032, 0.5027 and 0.5026. Calculate the confidence interval at 95 and 99% level. t95% = 2.36; t99% = 5.30
3. The following molar concentrations were obtained from replicate standardization of a solution: 0.5026, 0.5029, 0.5023, 0.5031, 0.5025, 0.5032, 0.5027 and 0.5026. Calculate the confidence interval at 95 and 99% level. t95% = 2.36; t99% = 5.30
Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.10QAP
Related questions
Question
Answer question #3 of this problem
![Answer all questions completely.
1.
Replicate water samples are analyzed for water hardness with the following results:
102.2, 102.8, 103.1 and 102.3 ppm CaCO3. Calculate the a) average deviation b) standard
deviation c) range.
2. Given the following data on the establishment of the precision of a method:
22.23, 22.18, 22.25, 22.09 and 22.17%.
Is 22.09 % a valid measurement at 95% confidence level? Qtab = 0.710
3.
The following molar concentrations were obtained from replicate standardization of a
solution:
0.5026, 0.5029, 0.5023, 0.5031, 0.5025, 0.5032, 0.5027 and 0.5026. Calculate the confidence
interval at 95 and 99% level. t95% = 2.36; t99% = 5.30](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd8b484c1-65aa-4dd8-913d-0daa6141acc3%2Faa4819ba-ad79-497d-87ef-b9eaa77b3a4f%2Fgfg1iyr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Answer all questions completely.
1.
Replicate water samples are analyzed for water hardness with the following results:
102.2, 102.8, 103.1 and 102.3 ppm CaCO3. Calculate the a) average deviation b) standard
deviation c) range.
2. Given the following data on the establishment of the precision of a method:
22.23, 22.18, 22.25, 22.09 and 22.17%.
Is 22.09 % a valid measurement at 95% confidence level? Qtab = 0.710
3.
The following molar concentrations were obtained from replicate standardization of a
solution:
0.5026, 0.5029, 0.5023, 0.5031, 0.5025, 0.5032, 0.5027 and 0.5026. Calculate the confidence
interval at 95 and 99% level. t95% = 2.36; t99% = 5.30
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