3. Suppose M8=x and M9=y. After each instruction has been executed, what is the content of the location indicated in column 3? Fill the contents in the table. Content MMR M8 R1 MMR M9 R2 Address Locations Register 1 Register 2 Accumulator M7 Content M1 M2 M3 ADD R1 R2 М4 МAМ M7 M5 HLT M7
Q: Given the binary format of an instruction as follows: 0000 1101 0110 1100 1010 1011 0001 0111 a.…
A: Actually, binary numbers are nothing but a 0's and 1's.
Q: Assume that the physical address of the instruction is (D6A92H) and the code 2 Bandwidth segment…
A: Memory addressing schemes:1. An Absolute Address, such as 04A26H, is a 20 bit value that directly…
Q: A. Add the necessary forwarding paths for the following instructions. A 1 add R3, R3, R4 IDEX EXMEM…
A: Here paths mean the Datapath. A data path is a path of how data flows. Any element in the datapath…
Q: The physical address of the following memory location specified in the instruction MOV [BX-0200H],…
A: The physical address for the instruction MOV [BX + 0200H], AL is 61200H.
Q: b) Given the following register and memory values, what values do the following ARM instructions…
A: Value of R0 register is given below after each given ARM instructions
Q: 22: The content of the top of a memory stack is 5420. The content of the stack pointer SP is 1789. A…
A: Answer : I attached an answer please have a look once.
Q: Given the X86-64 assembly instructions below, suppose variable "a" and "b" are long int data…
A: Lets do this line by line : 1. movq %rbx , %edx This moves the contents of register rbx into edx.…
Q: If r0 = 0x20000000 and r1 = 0xC3B2A, after STR r1, [r0], #4 instruction is executed, which of the…
A: If r0 = 0x20000000 and r1 = 0xC3B2A, after STR r1, [r0], #4 instruction is executed the following is…
Q: Consider a hypothetical machine with the following characteristics: a. instruction format: (total of…
A:
Q: Use the register and memory values in the tables below for the next questions. Assume a 32-bit…
A: a) add $t3, $t2, $t1 implies adding the contents of register t1 to the contents of register t2 and…
Q: Given the following memory values and a one-address machine with an AC. Word 20 contains 40 • Word…
A: Qualities stacked by the directions: Consider the given words and the information appeared in the…
Q: Register Content Data Memory Content wo Ох1006 Ох1000 O×FEB1 W1 ОХАВУА Ox1002 Ox0193 w2 w3 Ох0015…
A: Zero Flag (Z) : After any arithmetical or logical operation if the result is 0 (00)H, the zero flag…
Q: i)Write a program to evaluate the arithmetic statement: X= A*(B+C)+ D/(E*F) (a) three address…
A: According to the question, we have to write a program to evaluate the arithmetic statement. And the…
Q: A computer uses a memory unit with 256K words of 32 bits each. A binary instruction code is stored…
A: To find operation code, the register code part, the address part.
Q: Consider a hypothetical machine with the following characteristics: a. instruction format ; (total…
A: part 1: As, IR contain both opcode and address First instruction is LDA 20 ; load A from memory…
Q: 2. Write an instruction sequence that will initialize the ES register with the immediate value…
A: Q)Write instruction sequences that will initialize the ES register with the immediate value 1020H.…
Q: Suppose that BSR=05, TBLPTRL=04, TBLPTRH=05 FSR1L=04 FSR1H=04 Write one instruction that increments…
A: Dear Student, FSR1 currently points to 404H to make it point to 405H We need to increment FSR1.
Q: Assume that an LC-3 machine instruction "0011000000000110" is stored at address Ox3702, label A…
A: Solution:- Answer is (c) - ST RO,A
Q: 3. Explain in paragraph format what is happening in this example: Address >Add Instruction memory…
A: Introduction to Pipelining Pipelining is a method of breaking down a sequential process into…
Q: Instead of $t1 having the value of x as in previous question, suppose $a0 contains the memory…
A: In above question we find that,what instruction should be used to load the value to $t1.
Q: Suppose that you have a computer with a memory unit of 24 bits per word. In this computer, the…
A: In reality, binary numbers are nothing more than 0's and 1's.
Q: Consider the one-bus CPU organization below: 1ofrom external Data Control Unit to external Address…
A: Given question has asked to write the sequence of micro-instructions necessary to perform the…
Q: Consider a hypothetical machine with the following characteristics: a. instruction format : (total…
A: Note: as per guidelines we have provide solution for first 3-sub part . please repost the question…
Q: c. Draw the memory map and show the values of the affected registers and memory locations. assuming…
A: The Answer is
Q: 4. Consider the following high-level code snippets. Assume the (signed) integer variables g and h…
A: (i) if ( g >= h) temp = g+h; h= temp; else temp = g-h; h = temp…
Q: 1. T/F - if (B)=006000 (PC)=003600 (X)=000090, for the machine instruction 0x032026, the target…
A: Actually, register is a used to stores the data\information.
Q: Suppose that you have a computer with a memory unit of 24 bits per word. In this computer, the…
A: Actually, binary numbers are nothing but a 0's and 1's.
Q: Suppose that you have a computer with a memory unit of 24 bits per word. In this computer, the…
A: We need to find answers to questions based on given computer.
Q: (b) Suppose that the following instructions are found at the given location in memory. Illustrate…
A: Below I have Provided handwritten solution to the given question:
Q: 2- Find the physical destination address of last instruction below MOV BX,0AAH MOV AX,1BBH MOV DS,AX…
A: Please give positive ratings for my efforts. Thanks. ANSWER BX = 0AA H AX = 1BB H DS = AX = 1BB…
Q: Answer the following questions pertaining to the example program given. After the program is…
A: After the program is executed, list the values contained in each of the registers, and memory…
Q: Execute the following program using (a) Stack Architecture Instruction Set (b) Accumulator…
A:
Q: If R0 = 0x20008000, after STMDA r0!, {r3, r9, r7, r1, r2} instruction is executed, register r7 will…
A: STMDA, Store Multiple Decrement After (Store Multiple Empty Descending) stores multiple registers to…
Q: 16. If the first instruction "LXI H, 1100H" is positioned at address 7000H in memory, at what…
A: Correct answer of above given question is Option(1) 7003H i.e next instruction is located at address…
Q: Compute the binary representation of the following mips instruction: lw $t4, 5($s4)
A: opcode => lw => 100011 base => $s4 => 10100 rt => $t4 => 01100…
Q: 2. Given the following series of instructions (left two columns). After each instruction has been…
A: In computer engineering, computer architecture is a set of rules and methods that describe the…
Q: Assume a 32-bit machine with the register and memory values shown in the táble. instruction below…
A: In assembly Language the addressing modes can be given by: (1) Immediate Addressing Mode: In this…
Q: NAME: Registers A = 07H B = 16H D = ACH H = 34H C = FFH E = EDH L = 55H Quiz #5 Memory Map Write…
A: We need to write an assembly program using 8085 for the given scenario. * Since particular memory…
Q: f you have AX-0208H, BL-D8H, the results of performingII a. 00F3 H b. F300 H c. 5802 H d. 0258 H he…
A: 3. If you have AX=0208H, BL=D8H, the result of performing IDIV BL in AX is: a. 00F3H…
Q: Suppose R1 contains 0005 and R2 contains 0odc1, and the address of x is 00d1. What is the effective…
A: ff
Q: Suppose that you have a computer with a memory unit of 24 bits per word. In this computer, the…
A: Given: Suppose you have a computer with a memory unit of 24 bits per word . The assembly program…
Q: 8.1 Give the sequence of three-address code instructions corresponding to each of the follow- ing…
A: NOTE: As per bartleby guideliness for multiple question, we are supposed to answer only first…
Q: 2- For the MIPS assembly instructions below, what is the corresponding C statement? Assume that the…
A: The answer is given below:-
Q: For sub $rd, $rs, $rtReg[rd] = Reg[rs] + Reg[rt] - Which resources (blocks) perform a useful…
A: Answer:)
Q: A. Assume that the Instruction Pointer, EIP, contains 9610 and the assembly language representation…
A: Please Note: As per guidelines, we are supposed to answer only the first three parts only. Kindly…
Q: 2. Consider the initial value of register Stia Ox12345678 and the content of memory location…
A: Consider the initial value of register $t1 is 0x12345678 and the content of memory location…
Q: Given the binary format of an instruction as follows 0000 0011 0000 1000 1000 1000 0110 0011 a. What…
A:
Q: Assume that before the instruction is executed, the flags are CF=0, ZF=0 and SF=0 and the Registers…
A: The OR operation refers to the addition of the DL. The DL is given as the 0*87, addition OR…
Q: 2. Given the following series of instructions (left two columns). After each instruction has been…
A: Register 4= contains the value of M6Register 5= contains value of M5
Q: Given the following snippet of byte addressable memory with the base address already loaded in…
A: Holds both instructions and data With k address bits and n bits per locationn is typically 8 (byte),…
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
- ADD [R1], R2, [R3]; Here [R1] and [R3] indicate memory locations pointed by R1 and R3 register respectively. Here the operand field next to opcode will hold the result at the end. Assume that the machine code of this instruction is loaded at address 1020H of the main memory. Also assume that the contents of registers R1, R2 and R3 are 2001H, 2002H and 2003H respectively. Moreover, 1000H, 2000H and 3000H are saved at memory addresses 2001H, 2002H and 2003H respectively. a) Draw a schematic diagram of a CPU, show its important functional units required to process this instruction.int i = 5; is a statement in a C program. A. during execution, value of i may change but not its address B. during execution both the address and value may change C. repeated execution may result in different addresses for i D. i may not have an associated addressThe following byte sequence is the machine code of a program function compiled with the Y86- 64 instruction set. The memory address of the first byte is 0x300. Note that the byte sequence is written in hex-decimal form, i.e., each number/letter is one hex-decimal number representing 4 binary bits, and two numbers/letters represent one byte. 630030F3020000000000000030F11E000000000000007023030000000 00000601061316211761F0300000000000090- Please write out the assembly instructions (in Y86-64 instruction set) corresponding to the machine codes given by the above bytes sequence, and explain what this program function is computing. The machine has a little-endian byte ordering.
- Write a program in HACK assembly, without using symbols, that computes thebitwise exclusive or (XOR) of the values stored in RAM[1] and the value of thememory location with address stored in RAM[2]. The result of the computationshould be stored in RAM[0].You can think of RAM[2] as being a pointer to where the second operand of the XORis stored.4. The Single Instruction Computer (SIC) has only one instruction that can do all operations our RISC-V does (you did a homework problem). The instruction has the following format sbn a, b, c # Mem[a]=Mem[a]- Mem[b]; if (Mem[a]- Mem[b]<0) go to PC+c For example, here is the program to copy a number from location a to location b: sbn temp, temp, 1 sbn temp, a, 1 sbn b,b, 1 sbn b, temp 1 Start: Design a single cycle datapath and control for this instruction set architecture.Computer organization and assembly language Please help me with this. I have to write line by line what each line of codes does. CODE IS BELOW: .model small .386 .stack 100h .data msg1 db 13, 10, "Enter any number --> ", "$" msg2 db "Enter an operation +,- * or / --> ",13, 10, "$" msg3 db "The Operation is --> ", "$" msg4 db "The result is --> ", "$" By_base dd 21 by_10 dd 10 ; 32 bits variable with initial value = 10 sp_counter db 0 ; 8 bits variable with initial value of zero disp_number dd 0 ; 32 bits variable with initial value = 0 disp_number2 dd 0 disp_number3 dd 0 op_type db 0 last_key dd 0 ; 32 bits variable with initial value of zero remainder db 0 .code main proc mov ax,@data;set up datasegment movds,ax mov dx,offset msg1 call display_message callm_keyin calloperation mov dx,offset msg1 calldisplay_message callm_keyin cmpop_type, "+" jnz short skip_plus callop_plus skiP_plus: cmp op_type, "-" jnz short skip_minus callop_minus…
- 5. Write an assembly language program that inputs the number of a student from the keyboard and after the entry, it displays the number at the centre of the text screen in vertical manner. For example, if you enter your student number as 87138 it will be displayed at the centre of the monitor in the following way: 8 7 1 3 8 Hints: INT 21H, AH= 0AH inputs a string of data from the keyboard. The interrupt requires that the offset address of the buffer is in DX. INT 21H, AH= 02 outputs a character to the monitor and assumes the character in DL (ASCII). INT 10H, AH= 02 sets cursor location and assumes row in DH and column in DL.MIPS Simulator QtSpim: You are to have a complete program in MIPS assembly language that behaves exactly as the included C program. This program contains four functions in addition to the main() one. Your solution must contain all five C routines as they have been coded in the example. Make sure to run the program in MIPS and show the same output on MIPS as well to make sure there are no errors. Below is the five C routines and attached is the image of what the output must print out on QtSpim. #include <stdio.h> int getMax(int arr[], int n){int mx = arr[0];for (int i = 1; i < n; i++)if (arr[i] > mx)mx = arr[i];return mx;}void countSort(int arr[], int n, int exp){int output[n];int i, count[10] = { 0 };for (i = 0; i < n; i++)count[(arr[i] / exp) % 10]++;for (i = 1; i < 10; i++)count[i] += count[i - 1];for (i = n - 1; i >= 0; i--) {output[count[(arr[i] / exp) % 10] - 1] = arr[i];count[(arr[i] / exp) % 10]--;}for (i = 0; i < n; i++)arr[i] = output[i];}void…Computer Science Using memory-mapped I/O and polling, write a function print_string that prints a string onthe display, without using any system call. The address of the string is passed in register $a0and the string must be null-terminated. Test this function by calling it from the main function.Make sure to activate the “Keyboard and Display MMIO Simulator”.
- please use python language instruction- 1. Read the code from line 123 to line 137. This is the basically the selection. Remember how we talk about there are certain things about controlling population? Please explain how we make sure that the population, when going through a selection, does not shrink over generation. You may simply explain this as comments in a Python file as opposed to in a Word file:. Note that the code from line 123 to line 137 is divided into two small blocks. Use that as 2. The code we've just examined has one functionality of selection. So, we really should wrap that into one function nanied 'select'. Note that in this file there is no class named 'Population'. So, you should make this function a static method that belongs to the class named 'Individual', or a simple function that resides outside the class named 'Individual'. Please think about what the inputs and output of this function are before you start coding. Once you have created the…The codes below are disassembled from a program. Write an invalid target for the “jmp” instruction such that the code can be considered as anti-disassembly. Jmp ??? loc_2: call 15FF2A1h OR [ecx], d1 inc eax jmp short loc_3 db 0E8h Please just give me a simple answerBranches and Branches Here is a portion of a program. The initial condition codes have the values N = 0, Z = 1, and P=0. Consider the values for these codes after the LC-3 executes the sequence of instructions starting at address X384F. X384F 0101111111100000 X3050 0000100000000001 x3051 | 0000001000000010 x3052 0001000000111111 x3053 0000101000000001 x3054 0001111111101111 Value in condition cell N: Value in condition cell z: Value in condition cell P:
