3-7 3-3) Find the TRUE magnitude and direction of the RESULTANT FORCE and MOMENT AT POINT A 4' e 500lb/ft 3'- 2 (3) 22- 91009 50% 300lb 91009 4 1" 5 6 O (3) 30° FORCE AND COMPONENT DIAGRAM 250lb -32214 (4) 6 7
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Given:
Find the TRUE magnitude and direction of the RESULTANT FORCE and MOMENT AT POINT A.
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- F1 F2 a F3 A d. F4 Consider the following values: F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 12.7 kN.m c) - 74.6 kN.m d) 52.9 kN.m e) 24.1 kN.m f)- 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) 2.7 kN.m c) 31.6 kN.m d) 8.9 kN.m e) 5.4 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) 51.1 kN.m c) 14.6 kN.m d) 27.9 kN.m e) 74.1 kN.m ) 35.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 17.8 kN.m b) 82.7 kN.m c) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m f) 30.1 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting ) 321.3 kN.m a) 111.7 kN.m b) 218.1 kN.m c) 254.6 kN.m d) 93.1 kN.m e) 101.1 kN.m boQ4: The force in the Figure acts on the hook. Express it as a Cartesian vector. F = 675N (총)(S m) 2 m FB.uB (675)(0.7936i + 0.5151j+0.3282k) O FB.uB = (675)(-0.7936i + 0.5151j-0.3282k) FB.uB = (675)(-0.7936i - 0.5151j+0.3282k) FB-uB = (675)(-0.7936i + 0.5151j+0.3282k) O5. A person pulls on a rope with a force of 100 lbs as shown below. What is the moment about point A as a result of this pulling force? Answer: 3034 ft-lb CW 200 le 10 ft 18 ft Gin A * 40 ft SA
- F1 F2 a C F3 A d F4 D Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 = 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 = 10 kN; a = 30° , e = 45° B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 111.6 kN.m b) 112.6 kN.m c) - 184.6 kN.m d) - 109.6 kN.m e) - 104.1 kN.m f) None of them 2] What is the resultant moment of the five forces acting on the rod about point B? a) -95.8 kN.m b) 42.7 kN.m c) 80.9 kN.m d) 10.9 kN.m e) 51.8 kN.m f) None of them 3] What is the resultant moment of the five forces acting on the rod about point C? a) 32.6 kN.m b) - 21.1 kN.m c) 17.4 kN.m d) - 16.5 kN.m e) 15.6 kN.m ) None of them 4] What is the resultant moment of the five forces acting on the rod about point D? a) 37.6 kN.m b) 73.8 kN.m c) 71.6 kN.m d) 52.1 kN.m e) 21.1 kN.m f) None of them 5] What is the moment of the force F2 about point E? a) 90.7 kN.m b) - 88.1 kN.m c) 54.6 kN.m d) 103.1 kN.m e) 100.7 kN.m f) None of them 6]…F = (-6i + 4j+ 8k) kN PROBLEM 9 4 m Determine the moment of the force about Point P 0. Express the result as a Cartesian vector. 3 m 6 m 1 m A) 69.0 kN-m - B) 60 kN-m 2 m- * C) (-40i - 44j - 8k) kN-m • D) (40i + 44j + 8k} kN-m * E) (8i - 28j + 16k) kN-m Answer: C) (-40i - 44j - 8k) kN-m 25/38 250 PM O 55°F AOG A d* 12/13/202 P Type here to search hp ト Insert prt sc 144 esc & * backspace L. 8 Q こk A InstryF1 F2 a F3 A d. F4 E Consider the following values: - F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m3; F1 = 5 kN; F2 = 6 kN; F3 = 7 kN; F4 8 kN; F5 9 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 78.4 kN.m b) 82.7 kN.m c) - 54.6 kN.m d) 92.9 kN.m e) 24.1 kN.m f) - 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) - 201.6 kN.m c) 131.6 kN.m d) - 128.9 kN.m e) 215.4 kN.m f) - 144.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 186.7 kN.m b) 211.1 kN.m c) -209.1 kN.m d) 127.9 kN.m e) -174.1 kN.m f) 35.3 kN.m
- 3一4 Problem 1 Find the centroidal coordinates for the following triangles using the integrals SycdA S dA and %3D = X vp S You may utilize symmetry when appropriate. (-3,4) (3,4) (0,0) a. (5,4) (5,1) b. (4'0) (0) C. ×て (3,4) す Th-てh:8018 (-)HOME WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B,C (x, y, z) 2- Find FAR and FAC 3- Find |raR| and Iracl 4- Find FAR = F UAB and FAC = F UAC 5- Finally find R and a, B,Y 3m Fc= 500N FB= 500N 3m 5m 3m B 4m 2m 5mTwo forces act on the rod shown in Fig. 4-15a. Determine the resultant moment they create about the flange at O. Express the result as a Cartesian vector. F, =1-601 +40j + 20k) Ib 2 ft 4 ft B 5 t F; = (80i + 40j - 30k} lb t. (b) (a)
- F2 a F3 F4 E B Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 -= 10 kN; a = 30° , e= 45° ,B= 60e 4] What is the resultant moment of the five forces acting on the rod about point D? a) 37.6 kN.m b) 73.8 kN.m e) 71.6 kN.m d) 52.1 kN.m e) 21.1 kN.m ) None of them 5] What is the moment of the force F2 about point E? b) - 88.1 kN.m a) 90.7 kN.m e) 54.6 kN.m d) 103.1 kN.m e) 100.7 kN.m ) None of them 6] What is the resultant moment of the five forces acting on the rod about point E? a) 28.8 kN.m b)-85.4 kN.m e) 111.6 kN.m d) 90.9 kN.m e) 85.4 kN.m f) None of themF1 F2 a F3 A B d b F4 E F5 Consider the following values: - a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 1 kN; F3 = 4 kN; F4 = 6 kN; F5 = 8 kN; a = 30°, e = 60° %3D B = 30° %3D 1] What is the resultant moment of the five forces acting on the rod about point A? a) 85.8 kN.m b) – 21.1 kN.m c) - 13.5 kN.m d) 7.9 kN.m e) 24.1 kN.m f) - 57.8 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 188.8 kN.m b) - 153.5 kN.m c) 111.6 kN.m d) - 98.9 kN.m e) 85.4 kN.m f) - 244.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186 kN.m b) - 171 kN.m c) 155 kN.m d) 279 kN.m e) 423 kN.m f) 353 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 117.8 kN.m b) - 184.2 kN.m c)– 211.9 kN.m d) 126.9 kN.m e) - 27.1 kN.m ) 125.1 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting f) 32.3 kN.m a) 11.7 kN.m b) 19.8 kN.m c) 54.6 kN.m d) 9.1 kN.m e)…F1 F2 a C F3 A F4 D Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 = 3 kN; F2 = 11 kN; F3 = a = 30°, 0 = 60° , B = 30° 2 kN; F4 = 20 kN; F5 = 2 kN; 1] What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m ) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m ) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m ) 60.1 kN.m 5] What is the moment of the force F2 about point E? Activate W a) 122.7 kN.m b) 108.1 kN.m c) 66.6 kN.m d) 83.1 kN.m e) 111.1 kN.m ) 151.3 kN.m Go to Setting