25°C, the enthalphy of formation of gaseous nitric acid is -134 KiloJoules per mole. Calculate the change in internal energy (in kilojoules per mole) for the reaction below. (1/2)H2(g) + (1/2)N2(g) + (3/2)O2 -->HNO3(g)
25°C, the enthalphy of formation of gaseous nitric acid is -134 KiloJoules per mole. Calculate the change in internal energy (in kilojoules per mole) for the reaction below. (1/2)H2(g) + (1/2)N2(g) + (3/2)O2 -->HNO3(g)
Chapter6: Thermochemistry
Section: Chapter Questions
Problem 111AE: At 298 K, the standard enthalpies of formation for C2H2(g) and C6H6(l) are 227 kJ/mol and 49 kJ/mol,...
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At 25°C, the enthalphy of formation of gaseous nitric acid is -134 KiloJoules per mole. Calculate the change in internal energy (in kilojoules per mole) for the reaction below.
(1/2)H2(g) + (1/2)N2(g) + (3/2)O2 -->HNO3(g)
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