20 kM 3 kN t= 0 5 µF 5 kN 1 kN 12 V 10 k2
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- You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.
- You are working in an industrial plant. You have been instructed to double the capacitance connected to a machine. The markings on the capacitor, however, are not visible. The capacitor is connected to 560 volts and an ammeter indicates a current of 6 amperes flowing to the capacitor. What size capacitor should be connected in parallel with the existing capacitor? What is the minimum AC voltage rating of the new capacitor? What is the minimum DC voltage rating of the new capacitor? What is the minimum KVAR size that can be used in this installation?Three capacitors having capacitance values of 20F,40F, and 50F are connected in parallel to a 60 - Hz power line. An ammeter indicates a circuit current of 8.6 amperes. How much current is flowing through the 40F capacitor?In the figure ɛ = 10.0 V, R1 = 4.00 N, and R2 = 1.00 N. The inductor is ideal. If the switch is closed for a long time, what is the current through the inductor. Give your answer in A. Şekildeki devrede ɛ = 10.0 V, R1 = 4.00 N , ve R2 = 1.00 N olarak verilmişlerdir. Solenoidin iç direnci yoktur. Anahtar kapatıldıktan çok uzun süre sonra solenoidden geçen akım A cinsinden nedir. R1 R2 L E Yanıtınız
- 152130 222 Ⓒ520° Fj² 7 Find voltage drop Mutual inductance Majt = + {1.2 V. on 12 resistance Nex (the same for all10.0 V, R1 = 4.00 N , and R2 = 1.00 N. The In the figure ɛ = inductor is ideal. If the switch is closed for a long time, what is the current through the inductor. Give your answer in A. Şekildeki devrede ɛ = 10.0 V, R1 = 4.00 N , ve R2 = 1.00 N olarak verilmişlerdir. Solenoidin iç direnci yoktur. Anahtar kapatıldıktan çok uzun süre sonra solenoidden geçen akım A cinsinden nedir. R1 S E R2 L leIn the figure R1 When the switch is opened after having been closed for a long time, the current in the inductor drops from 1.00 A to 0.250 A in 0.200 s. = 4.00 N , and R2 = 1.00 N. The inductor is ideal. What is the inductance of the inductor in mH? = 1.00 N olarak verilmişlerdir. Şekildeki devrede R1 = 4.00 N , ve R2 Solenoidin iç direnci yoktur. Anahtar uzun süre sonra kapalı kaldıktan sonra açılırsa solenoidden geçen akım 0,200 s içinde 1,00 A değerinden 0,250 A değerine düşmektedir. Solenoidin indüktansı mH cinsinden nedir? %3D R S E -R2 L
- 1. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.Calculate values of asked physical quantities of the circuit in the figure. What is the capacitance of system 23? C23 C₁ = 3.0 F What is the capacitance of system 123? C123 = F C₁ = 2.0 F What is the capacitance of system 45? C45 = F Your last answer was interpreted as follows: 1 Your last answer was interpreted as follows: 1 What is the charge in the capacitor system? C Your last answer was interpreted as follows: 1 What is the total capacitance of the system? F Value 8.8500 x 10 EO Quantity permittivity of free space capacitance capacitance capacitance capacitance capacitance Your last answer was interpreted as follows: 1 capacitance of system 23 capacitance of system 123 capacitance of system 45 Your last answer was interpreted as follows: 1 Do not leave any fields blank. If you don't know the answer, insert 1 for example. Insert the answer with 3 significant digits without rounding the answer. Constant U = 7.0 V Unit E Symbol €0 C₁ = 3.0 F C1 C₂ C3 C4 C5 C23 C₂ = 9.0 F C₂ = 3.0 F…In the figure ɛ = inductor is ideal. If the switch is closed for a long time, what is the 10.0 V, R1 = 4.00 N , and R2 = 1.00 N. The current through the inductor. Give vour answer in A. R1 S E R2 L