2. PARALLEL-PLATE CAPACITORS. The plates of a parallel-plate capacitor in vacuum are 5.00 mm (5.00 x 10^-3 m) apart and in area 2.00 m². A 10.0kV (10,000 V) potential difference is applied across the capacitor. Compute (a) the capacitance; and (b) the charge on each plate.

2. PARALLEL-PLATE CAPACITORS. The plates of a parallel-plate capacitor in vacuum are 5.00 mm (5.00 x 10^-3 m) apart and in area 2.00 m². A 10.0kV (10,000 V) potential difference is applied across the capacitor. Compute (a) the capacitance; and (b) the charge on each plate.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 37P

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Concept explainers

Dielectric Constant Of Water

Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.

Electrostatic Potential and Capacitance

An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.

Question

2. PARALLEL-PLATE CAPACITORS. The plates of a parallel-plate capacitor in vacuum are 5.00 mm (5.00 x
10^-3 m) apart and in area 2.00 m². A 10.0kV (10,000 V) potential difference is applied across the
capacitor. Compute (a) the capacitance; and (b) the charge on each plate.

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