TRIBUTARY METHOD OF LOAD DISTRIBUTION(3)2. Consider the floor plan shown inFigure. The floor is 100mm thickF-6 @ 6.67' = 40%3DC4I-reinforced concrete. Determine theB2GIB3following:(a) load that acts on floor beam B1,(b) load that acts on beam B5,(c) the load acting on cornercolumn C1, and(d) the load acting on interiorB42 @ 10' = 20'B)C2I- B5 –I-IG4G2G3B15 @ 8'= 40'column C2©-I-C3Ci40'20*Neglect the weight of joists

Floor plans are generally scaled drawings that define the relationship between rooms and other…

Answered: 2. Consider the floor plan shown in…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Help me how to design the REINFORCED CONCRETE BEAMS WITH IRREGULAR CROSS SECTION as shown infigure 1 using the following parameters:F’c = 3,500 Psi Fy=Grade 40 Stirrups = Φ10mmMu = 200 Kn-M All Concrete cover = 30mm Es=200,000 Mpa Find the following: AC area of compression concrete stress block in mm. Assume z = 0.85dEff a height of compression concrete stress block in mm. c distance from the neutral axis to outermost compression fiber in mm. z actual moment arm for Mu=ØTz in mm. As actual area of tension steel in sq.mm. N quantity of Ø20mm steel rebars ЄS Actual Strain of steel ЄY Yield Strain of steel Check if the beam is singly reinforced concrete in the designed then concludeCheck: ЄY < = > ЄS Draw the Working Drawings of the x-section.
Q2// A floor system consists ofconcrete slab supported by continuous beam h = 140mm , bw = 300mm,d = 550mm, f 28MPA, fy = with: %3D 420MPа. Determine the steel reinforcement required at mid span of interior beam to resist service dead load moment Ma = 320KN.m and service live load moment M = 250 kN.m %3! %3D 8m + 3m 4 3m 3m 1-1
The concrete post is reinforced axially with four symmetrically placed steel bars, each of cross-sectional area 900 mm2. Compute the stress in each material when the 1000-kN axial load is applied. The moduli of elasticity are 200 GPa for steel and 14 GPa for concrete. Compatibiltiy Equation . Ust Bearing |1000 kN plate Steel- Concrete 300 mm 300 mm Section a-a
ス F. reinforced concete structure is shown The floor framing plan oF in the figure. The beams are 280 mm wide and S20 mm deep, and the slob is 110mm thick an edditional (super impes) veight,1 and live lo ad of OTher than conerete weight, the floor subjected other to Is dead load of 3k Pa si2 k Por. Unit weight of concrete is 23.5 kN/m® le Determine the total uniform load on beam DEF and ABC axial load 20 Determme the total on columns A and B,D an) E 2Sm 티 2.Sm 6.2m 6.2m
A simply supported beam is reinforced with 5-ϕ25 mm at the bottom and 2-ϕ20 mm at the top of the beam. Concrete covering to the centroid of reinforcement is 70 mm at the top and 64 mm at the bottom of the beam. The beam has a gross depth of 450 mm and gross width of 300 mm. fc’= 28 MPa, fy = 415 MPa. Assume bars are laid out in a single layer. Calculate the following if the limiting tensile steel strain is 0.004 for a ductile failure: a. Depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number (in mm) b. Design strength of the beam section to the nearest whole number (in kN·m) c. Maximum service uniform live load over the entire span in addition to a DL = 20 kN/m (including the weight of the beam) if it has a span of 6 m (in kN/m & to the nearest whole number)
a concrete floor slab 100mm thick is cast monotholic with concrete beams 2.0 m on centers. the beams have a span of 4.0m, web width of 259 mm and overall depth of 50 mm. the tensile reinforcement consists of 6-⌀20 mm bars in two rows with 25mm vertical clear spacing. use material strengths f'c=21MPa and fy=415MPa. calculate the ff considering a T-geometry: 1. effective flange width of an interior beam in mm 2. depth of uniform stress block at ultimate stage in mm to the nearest whole number 3. tensile steel strain compatible strain of 0.003
Design the reinforcement of the cantilevered slab (CS – 1) in Figure 3. The slab is to be used for terrace occupancy with a designed floor live load of 4.80 kPa. Use 12mm dia deformed bars as main reinforcement and 10mm dia bars for temperature reinforcement. Also, use fc’ = 20.7 MPa and fy = 276 MPa. Draw the structural details of the slab.
The 5-story building design project will have its beams and slab poured monolithically and formed a T- section as shown. Determine the design strength pMn in accordance with the ACI/NSCP Code. The tension steel is 9- 36 mm diameter bars (As of 36 mm = 1006 mm2) with three bars in each of three layers. Assume 12 mm stirrups are used, and there is 25 mm between layers. Use fc': 28 MPa and fy = 413.70 MPa. 750 mm T175 mm 1000 mm 9-36 mm diameter bars 350 mm
a simply supported beam is reinforced with 4-diameter28mm at the bottom and 2-diameter 20mm at the top of the beam. concrete covering to centroid of reinforcement is 70mm at the top and 64mm at the bottom of the beam. the beam has a gross depth of 450mm and gross width of 300mm. f'c=28MPa, fy=415MPa. assume bars laid out in single layer. calculate the ff if the limiting tensile steel strain is 0.004 for a ductile failure: 1. depth of the neutral axis from the extreme concrete compression fiber to the nearest whole number in mm 2. design strength of the beam section to the nearest whole number in kN.m 3. maximum service uniform live load over the entire span in addition to a DL=20kN/m (including the weight of the beam) if it has a span of 6m in kN.m
1.2m 10 cm O 7cm -7cm O This concrete beam has four A-35 steel rods of one centimeter diameter and a square cross section. It experiences a compressive axial load of 200kN. You must calculate the stresses developed in the two components in the figure.
Subject: Reinforced concrete Design- Civil Engineering A rectangular beam has a width of 300mm and an effective depth pf 537.50mm to the centroid of tension steel bars. Tension reinforcements consists of 6-28mm bars in two rows, compression reinforcement consists of 2-22mm bars, fc' = 27.6MPa, fy = 414.7MPa, d'=60mm. The depth of compression block is _mm. Choices: A. 137mm B. 213mm C. 173mm D. 231mm
Design the slab reinforcement if the maximum positive moment is Mup=wul2/11 . and the maximum negative moment is Mup=wul2/19. Include the design for S&T bar. Given: length = 6m span = 2m Wu= 8.572 kPa Slab thickness = 150 mm f'c = 28 MPa fy= 219 MPa main bar = 10 mm s&t bar = 8mm

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