2. a) Calculate the hard-sphere (HS) collision theory rate constant ks for the reaction NO(g) + C₁₂(g) Þ NOCl(g) + HS Cl(g) at 300 K in units of dm³ mols. The collision diameters of NO and Cl₂ are 370 and 540 pm, respectively. 16.0 g/mol, and mcı Use masses of m₁ = 14.0 g/mol, mo = 35.0 g/mol. N = b) Now include the line-of-centers (LOC) energy criterion to find koc in units of dm³ mol¹ s¹ using E₁ = 84.9 kJ mol LOC LOC c) Calculate the ratio of kчs and kLoc to the experimental rate constant at 300 K given A = 3.981 10° dm³ mol¹ s and E₁ = 84.9 kJ mol‍¹. a -1

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section: Chapter Questions
Problem 66GQ
Question
2.
a) Calculate the hard-sphere (HS) collision theory rate
constant ks for the reaction NO(g) + C₁₂(g) Þ NOCl(g) +
HS
Cl(g) at 300 K in units of dm³ mols. The collision
diameters of NO and Cl₂ are 370 and 540 pm, respectively.
16.0 g/mol, and mcı
Use masses of m₁ = 14.0 g/mol, mo
= 35.0 g/mol.
N
=
b) Now include the line-of-centers (LOC) energy criterion
to find koc in units of dm³ mol¹ s¹ using E₁ = 84.9 kJ mol
LOC
LOC
c) Calculate the ratio of kчs and kLoc to the experimental
rate constant at 300 K given A = 3.981 10° dm³ mol¹ s
and E₁ = 84.9 kJ mol‍¹.
a
-1
Transcribed Image Text:2. a) Calculate the hard-sphere (HS) collision theory rate constant ks for the reaction NO(g) + C₁₂(g) Þ NOCl(g) + HS Cl(g) at 300 K in units of dm³ mols. The collision diameters of NO and Cl₂ are 370 and 540 pm, respectively. 16.0 g/mol, and mcı Use masses of m₁ = 14.0 g/mol, mo = 35.0 g/mol. N = b) Now include the line-of-centers (LOC) energy criterion to find koc in units of dm³ mol¹ s¹ using E₁ = 84.9 kJ mol LOC LOC c) Calculate the ratio of kчs and kLoc to the experimental rate constant at 300 K given A = 3.981 10° dm³ mol¹ s and E₁ = 84.9 kJ mol‍¹. a -1
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