2 (b) In the circuit below, we set a = (the figure is clearly not drawn to scale). Find the average power Ps supplied by the current source Isz. Im Is2. α |IS2| = 8 A Re IS2↑ Z₁ Z₁ = 2 Z₂ = 2j P₁ 64/W Ps + Z₂ Vx

2 (b) In the circuit below, we set a = (the figure is clearly not drawn to scale). Find the average power Ps supplied by the current source Isz. Im Is2. α |IS2| = 8 A Re IS2↑ Z₁ Z₁ = 2 Z₂ = 2j P₁ 64/W Ps + Z₂ Vx

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.7P: Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor,...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

2
(b) In the circuit below, we set a = (the figure is clearly not
drawn to scale). Find the average power Ps supplied by the
current source Is2.
Im
IS2
α
|IS2| = 8 A
Re
IS2↑
Z₁
Z₁ = 2
Z₂ = 2j
P₁ 64/W
Ps
+
Z₂ Vx

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