13. x = 2t + 6 and y = 4t – 1 for 0

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A: Solution...

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A: Since the student has posted multiple questions and does not mention any specific question, so we…

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A: For (B), We need to find the curve whose parametric equation is given above.

Q: Find dy/dx and d2y/dx2 , and find the slope and concavity (if possible) at the given value of the…

A: Differentiating with respect to t, we get Now slope at t = -2 is,

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A: NOTE: Refresh your page if you can't see any equations. . take derivative

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A: We can find the slope at the indicated point in the following steps.

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A: Differentiating with respect to t, we get

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Q: Find dy/dx and d2y/dx2, and find the slope and concavity (if possible) at the given value of the…

A: find the slope and concavity (if possible) at the given value of the parameter.

Q: Find dy/dx and d2y/dx2 , and find the slope and concavity (if possible) at the given value of the…

A: We have the parametric equations y=e-t=1et=1x At t=1, x=e, y=1e

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A: We will solve the problem

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Q: Find dy/dx and d2y/dx2 , and find the slope and concavity (if possible) at the given value of the…

A: Given that x=t-6  and  y=t2. This implies that, dxdt=1   and   dydt=2tdydx=2t1=2t Differentiate one…

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A: Consider the parametric curve  ct=3t3,3t2−3 To find : dydxt=4