4. Below are the IR regions and NMR chemical shifts table for use with the spectroscopy problems:'H NMR12RO=C11OH10 9ΟΞΟR-C-H1----- 008Nitrogen-15Oxygen-16Nitrogen-147Phosphorus-31Sodium-23Carbon-13ppm6H C=C-HOH5NHH-C-XH-C-O-OHX = F, Cl, Br(i.e. electronegative atom)3-NHWhich of the following isotopes is NOT NMR active?2H-C-NH-C-S1-CH3-CH₂-CEC-HH-C-C=O -CHH-C-C=CHC-004000DIDsmall rangerange of valuesbroad peak=C-H3250-3300N-Hbroad with spikes-33003500-O-Hbroad-3300-3400-O-H -CINCON-HHH2730-2820-C-Hof=CH3000- 2 peaks31002850-2960HO-C-O-Hbroad-30003000usuallystrong-CEN2200-CICH⇓22002500wavenumber, cm-¹2000CHC NH1600-16609801680AUOR1730O171031600NR₂165015001000-1.

According to the question, we need to identify which isotope is not NMR active.

10 9 8 Nitrogen-15 7 Oxygen-16 Nitrogen-14 Sodium-23 ppm Phosphorus-31 6 C=C-H 5 4 H-C-X H-C-O -OH X = F, Cl, Br (i.e. electronegative atom) 3 -NH 2 H-C-C=C 1 H-C-N H-C-S CEC-H H-C-C=O-CH HC-0 * Which of the following isotopes is NOT NMR active? -CH3 -CH₂- 0 4000 small range H range of values broad peak =C-H N-H 3250- 3300 broad with spikes -3300 3500 -0-H broad-3300 -3400 -0-H-CIN usually strong NH CHO H O H H 2730- 2820 O -C.OH broad-3000 3000 3000- 2 peaks 3100 -C-H 2850- 2960 -CEN 2200 -CICH ♡ 2200 2500 wavenumber, cm1 2000 CC HC N H 1600- 1660 O O C. 1680 OR 1730 O 1710 O 1600 NR₂ 1650 1500 1000

10 9 8 Nitrogen-15 7 Oxygen-16 Nitrogen-14 Sodium-23 ppm Phosphorus-31 6 C=C-H 5 4 H-C-X H-C-O -OH X = F, Cl, Br (i.e. electronegative atom) 3 -NH 2 H-C-C=C 1 H-C-N H-C-S CEC-H H-C-C=O-CH HC-0 * Which of the following isotopes is NOT NMR active? -CH3 -CH₂- 0 4000 small range H range of values broad peak =C-H N-H 3250- 3300 broad with spikes -3300 3500 -0-H broad-3300 -3400 -0-H-CIN usually strong NH CHO H O H H 2730- 2820 O -C.OH broad-3000 3000 3000- 2 peaks 3100 -C-H 2850- 2960 -CEN 2200 -CICH ♡ 2200 2500 wavenumber, cm1 2000 CC HC N H 1600- 1660 O O C. 1680 OR 1730 O 1710 O 1600 NR₂ 1650 1500 1000

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter13: Nuclear Magnetic Resonance Spectroscopy

Section: Chapter Questions

Problem 13.28P

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Similar questions

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2. READ THE DIRECTIONS TO EACH QUESTION CAREFULLY - not following the directions means you get the question wrong! 3. FORMAT YOUR ANSWERS AS DIRECTED - formatting your answers incorrect means you get the question wrong! 4. Below are the IR regions and NMR chemical shifts table for use with the spectroscopy problems: ¹H NMR 12 R 11 10 OH R D H 9 8 7 H ppm 6 C=C-H OH 5 NH H-C-X H-C-O -OH X = F, Cl, Br (i.e. electronegative atom) 3 -NH 2 H-C-N H-C-S CC-H H-C-C=C 1 H-C-C=O-CH HC-0 -CH3 -CH₂- 0 4000 DIO small range range of values broad peak =C-H N-H 3250- 3300 broad with spikes -3300 3500 -O-H broad-3300 -3400 -O-H -CIN N-H CO H =C ㅏ 2730- 2820 H 3000- 2 peaks 3100 C-H H 2850- 2960 O -C-O-H broad-3000 3000 usually strong -CEN 2500 wavenumber, cm-¹ 2200 <-CICH B 2200 2000 H 0 C 0:0 C. ပြီး 1680 1730 O OR 1710 1600- 1660 18%0.058 N 1650 viz NR₂ 1600 1500 D 1000
Q5. Identify the spectrum (A, B, C or D) one would obtain from analysis using Energy Dispersive Spectroscopy. Briefly explain why. SA Absorbance (au) Absorbance (au) 0.5 08. 04 00+ 400 LSTE AUNPS at 0 v 5C 600 Wavelength (nm) 100 Concentration of AuNPs (g/mL) -LSTENPS BSA GLY Naci CYS pH7 PM 9 150 LSTE AUNP F1 AUNPs F2 AUNPs 700 111 El Mntensity (%) D FIL 2 theta (degree) 58 5D