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- A. Amino Acids with Electrically Charged Side Chains Negative Pesitive Aspartie Acid Glutamie Acid (Asp D Lysine Histidine Arginine (Argl ® (Glul O (His H HO Ho HO -NH, -NH, NH, NH, -NH, NH NH H,N- ONH, ONH, C. Special Cases B. Amino Acids with Polar Uncharged Side Chains Proline Asparagine (Aan N Cysteine (Cya) © Glycine (Gly O Threonine Glutamine (Pra) P Serine (Ser 9 Но Họ Ho Ho Ho Но NH, NH, NH NH, NH, NH, -NH, но- SH он NH, NH, D. Amino Acids with Hydrophobic Side Chains Leucine (Leu O Phenylalanine (Phe e Tryptophan (Tp W Tyrosine Methionine Valine Isoleucine Alanine (Ala A IMe M Ho Ho Ho Ho HO NH, -NH, Но -NH, HO NH, NH, NH, NH, NH, NH он If the chromatogram was developed from reverse phase conditions, which of the following amino acids is expected to elute first? serine phenylalanine tryptophan O tyrosineAnswer the following questions on the basis of the free energies of formation at 25°C shown in the table at the top of the next page: (a) Does the peptide bond between alanine and glycine form spontaneously under standard conditions?pagenow.com/ry/takeAssignment/takeCovalentActivity d Paview pics Paturences the the References to access important valses if needed for this question Consider the following system at equilibrium where AH-10.4 kJ, and K = 55.6, at 698 K. H₂(g) + 1₂(9) 2HI(g) When 0.28 moles of 1,(9) are removed from the equilibrium system at constant temperature: The value of K The value of Qc K The reaction must Orun in the forward direction to restablish equilibrium. Orun in the reverse direction to restablish equilibrium. Oremain the same. It is already at equilibrium. The concentration of Hy will & more group attempts mean Submit Answer Platerences Use the References to access important values if needed for this question Consider the following system at equilibrium where AH 10.4 kJ, and K 1.80x102, at 698 K: 2HI(g) H₂(g) + 1₂ (9) If the TEMPERATURE on the equilibrium system is suddenly increased: The value of K A. Increases B. Decreases C. Remains the same The value of Q A. Is greater than Ke B. Is…
- (k) (1) Me. an allene CH₂ CO₂Me Ph N₂ a. TsN 3, DBU b. Rh₂(OAC)4 CO₂Me Rh₂(OAC)42. Protein: SHAYNERSE Predict the products of the following reactions with the protein given, if there is none, write NO RXN. a. Biuret reagentb. KOH/Pb(CH2COO)2c. Glyoxilic Acid/Conc. H2SOd. Hg/HNO3e. HNO3What is the ratio of CATION to ANION in Drug X? [blank1] H₂C -H Fogy CH3 SO42 'N CH3 Drug X CH3NH Describe the possible interactions between the SIDE CHAINS of amino acids: I. and II.... II. and III... I. and III... 1. COO NH3* 2 HO II. COO HO NH3* COO NH3* III.
- Q: 1.5%. Sucrose by massx M what volume f soft,dmink Solin Noitolu millimeter contain' 5:29 of Suvrose bolovitine 102 102 24A) nioino) 220 ud s d ro tnaroa 220M 220m VWrite reactions of isoleucine with the following reagents: a. HNO2; b. CH3COCl; c. t°C; d. HBr.The above amino acid, shown at pH = 7.0 and where every atom (including hydrogens!) is visible, is (D or L) -X-
- [Review Topics] [References] Draw a structural formula for the major ionic form of the amino acid shown below when in aqueous solution at pH 1.5. . O H₂NCH₂COH 0- You do not have to consider stereochemistry. You do not have to explicitly draw Hatoms. Do not include lone pairs in your answer. They will not be considered in the grading. VI/@ 81 ///// 262 As 000. [F3a) Consider a tripeptide (a peptide that's only 3 amino acidslong) composed of one molecule each of lysine, leucine, and thehypothetical amino acid lupine (which doesn't actually exist, sodon't try to look it up). Lupine has an ionizable side group with apa of 6.3. When this tripeptide is dissolved in an aqueoussolution at pH 5.0, the net charge on the molecule is +2. Givethe charge on the protonated form of the lupine side group, andthe charge on the deprotonated form of the lupine side group.show your work or explain how you determinedthe charge on each form of the lupine side groupsEthylenediamine has pK, values of 4.072 (pKb) and 7.152 (pKb2). What is the predominant form of ethylenediamine at pH 6.077? O) HẸNCH,CH,NH H₂NCH₂CH₂NH₂ H₂NCH₂CH₂NH What is the predominant form of ethylenediamine at pH 9.332? O H₂NCH₂CH₂NH₂ O H₂NCH₂CH₂NH O H₂NCH₂CH₂NH3 What is the second most abundant species of ethylenediamine at pH 6.077? O H₂NCH₂CH₂NH₂ O HẸNCH,CH,NH O H₂NCH₂CH₂NH What is the second most abundant species of ethylenediamine at pH 9.332? O H₂NCH₂CH₂NH₂ ( HẸNCH,CH,NH H₂NCH₂CH₂NH Calculate the percentage of ethylenediamine in the predominant form at each pH. pH 6.077: pH 9.332: % %