1. rB = 2.5 Q Vin = 10 V R= 100 Q Required: V and I using 1s, 2n0, and 3rd approximations (assume a Si diode)
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- How is a solid-state diode tested? Explain.Q4) Determine and sketch the output voltage across the load resistor (RL) for the circuit shown below. (assume Si diodes) V_DC 0.75 0.25 V_SIN Y SIN as RL -1 v SOR V_SQR 0.75 -0.75 V_TRI V TRI asQuestions 1 V, is a 60Hz source with a peak voltage VP-120V is feeding a rectifier, assume ideal diode. The load resistance has a value of R= 10 kn. If ripple voltage Vr = 2V, the Diode average current Ipavg is VI Select one: None b. 580mA 850mA O c. Od 245mA O e. 425mA D C C: R www Q+ Vo
- The cut-in voltage for each diode in the circuits shown in Figure Pl.30 is V, = 0.6 V. For each circuit, determine the diode current I, and the voltage Vo (mea- sured with respect to ground potential). Q7 R= 10 k2 Vo oVo Ip R= 10 k2 5 V 5V 5 V 5 V (a) (b) R= 10 k2 Vo 5V E 5 V (c)Determine the state of diode for the circuit shown and find ID, VD. Assume simplified model for the diode. 4k02 2V 1k02. Off, 0.00mA, 0.4V O Off, -0.005mA, 0.0v On, 0.48mA, 0.6v On, 0.55mA, 0.7v Option 5Draw the corresponding output waveform of the double diode partial limiter below using simplified diode model. Indicate all the necessary voltage levels and use Silicon diodes. 20 VP-P 1KQ M D1 9V D2 4.5V VOUT
- Consider the circuit in the figure below 4:1 120 V rms ooooo gll reelee D₁ L a. What type of circuit is this? b. What is the total peak secondary voltage? D₂ c. Find the peak voltage across each half of the secondary. d. Sketch the voltage waveform across RL. e. What is the peak current through each diode? f. What is the PIV for each diode? RL 1.0 ΚΩIn the clamping circuit below, assume the diode has Von-0.7V and V₁ is a sinusoidal wave with a peak-to-peak amplitude of 10V. How much is the maximum value of the output voltage signal (Vmax)? And how much will it be if we set V₂=2V? Input V1 C1 0.1e-6 9.3 V and 7.3 V 9.3 V and 11.3 V 11.3 V and 7.3 V O 7.3 V and 12.0 V O 12.0 V and 7.3 V Output D1 1N4148 .tran 30-3 V2 0 Vmax V(output) 0.0ms putput MAN Input 0.6ms 1.2ms V(input) 1.8ms 2.4ms 3.0ms1. For the Diode Circuits shown below, Vd=0.7v a. Draw the small signal eq. circuit b. find Vo (AC+DC) Sketch the output waveform Vo (AC+DC) C. + V1 vin C1 inf 9 11 R2 25 1m D1 dio R1 300 VO
- 2. Figure A.1 shows I-V characteristics of two diodes, namely A and B. Diode A has higher dynamic resistance than diode B. UTM &UT ID 4 5UTM 3TM UTM UTM &UTM 5 UTM & UTM UTM 3 UTM 03 TM 6 UT 0.68 (a) UTM VD Figure A.1 State one possible reason why the diodes have different knee voltage values. UTM OM & UTM 3 UTM & TM (b) Based on Figure A.1, identify the knee voltage of UTM" TM 5 UTde BE UTMAssuming an ideal diode model for all the diodes in the circuit below, chose the correct state (bias) for each diode. R1 ww 9kQ 1N1199C R2 D1 18kQ 1N1199C V2 12 V R3 1kQ D3 1N1199C R4 D3: On (Forward Bais) D3: Off (Reverse Bais)Question 1: In the circuit shown below, the output (Vo = 10V Max.) Unipolar. The frequency of Primary is 60 Hz. The diodes are Silicon with VD = 0.7V. a. Sketch the output without a Capacitor. b. Determine Voc without a Capacitor. c. Sketch Vs (at the Secondary). d. Determine Voc with a Capacitor of 10 uF across RL. e. Determine the RMS Value of Vp (at the Primary). f. PIV (Peak Inverse Voltage). 10:1 Output C. 22 k1 All diodes are IN4001. | 00000