1. In this lab you will be calculating the resistivity, you will first need to determine thecross sectional area (A) of each wire. If we consider a wire to be a long cylinder; then thecross sectional area would have a circular shape as shown by Figure 2 in theinstructions. Use equation (5) to calculate the cross sectional area for each wire.Note: Write down the areas in scientific notation and have 7 digits.MaterialDiameter (m)Cross – Sectional Area(m²)0.000408A =0.000713A2 =Brass0.000916Az =0.001170A4 =Copper0.000916Ag =%3DNichrome0.000916A, =Stainless Steel0.000916Ag =2. A student Mei who is doing the experiment measures a voltage V = 0.094954 V and acurrent I = 1.0747 A, then she uses equation (2) to calculate the resistance R. Whatvalue does Mei determine for R?3. Mei puts in her values and constructs a graph which gives her a slope of 0.0980244She then uses equation (7) and the cross sectional area of A, (from the calculations onquestion #1) to calculate the resistivity of the wire. What is the value of the resistivitythat she calculates? The resistance of a particular element depends on its geometry, the resistivity and the temperature. Resistivity is thetendeney of the material to behave as a resistor and is an inherent property of a material, in the same sense that density orthermal expansion are inherent properties. Materials with lower resistivity, like copper, are good conductors of electricityand widely used in eireuit components while those with larger resistivity, like rubber, are used as insulators.For a wire with length (L), cross-sectional area (A), and made from a material with resistivity (p) the resistance (R)will be given by the following equation:R = L(3)In case that the geometry (length and cross sectional area) and the resistance of the wire is known, then is possible tocalculate the resistivity solving equation 3:RA(4)A wire can be consider as a long eylinder; then the cross sectional area would have a circeular shape as shown inFigure 2.Cross SectionalAreaLengthFigure 2Then the cross sectional area of the wire can be caleulated using the equation of the area of a circle:A = mr?(5)In this experiment, you will measure V and I to determine R for various lengths of wire. You will then make a graphof Resistance (Y-axis) versus length (X-axis). The plot will result in a straight line that has a slope equal toslope = A(6)From equation 6, it is possible to solve the resistivity in terms of the slope and the cross sectional area:p= slope + A(7)The manufacture values of the resistivity corresponding to the wires used in the experiment are reported in Table 1.These values will be used as the theoretical when caleulating percent error.Table 1. Theoretical resistivity of different materials according to manufacturer.AttractedMaterialBrassColorDiameter (m)Resistivity (Qm)to MagnetYellowNo0.0005087.0 x100.0008130.0010160.001270CoppenRedNo0.0010161.8 x10*105 x10Dark Gray NoDark GrayNichrome0.001016StainlessYes0.00101679 x10*Steel

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1. In this lab you will be calculating the resistivity, you will first need to determine the cross sectional area (A) of each wire. If we consider a wire to be a long cylinder; then the cross sectional area would have a circular shape as shown by Figure 2 in the instructions. Use equation (5) to calculate the cross sectional area for each wire. Note: Write down the areas in scientific notation and have 7 digits. Material Diameter (m) Cross - Sectional Area (m²) 0.000408 A = 0.000713 Az = Brass 0.000916 Az = 0.001170 A4 = Copper 0.000916 Ag = Nichrome 0.000916 A, =

1. In this lab you will be calculating the resistivity, you will first need to determine the cross sectional area (A) of each wire. If we consider a wire to be a long cylinder; then the cross sectional area would have a circular shape as shown by Figure 2 in the instructions. Use equation (5) to calculate the cross sectional area for each wire. Note: Write down the areas in scientific notation and have 7 digits. Material Diameter (m) Cross - Sectional Area (m²) 0.000408 A = 0.000713 Az = Brass 0.000916 Az = 0.001170 A4 = Copper 0.000916 Ag = Nichrome 0.000916 A, =

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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