1. Check the compactness of W36x529, W21x48 and W14x99. 2. Verify the available flexural strength of W18×50 shape for the beam shown below. The unfactored loads are a uniform dead load of 0.45 kip/ft and a uniform live load of 0.75 kip/ft. Use the LRFD load combinations to find the required flexural strength. Wo 0.45 kip/ft w₁ = 0.75 kip/ft 35'-0" Beam Loading & Bracing Diagram (full lateral support)
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- Problem 1 Considering flexural buckling, determine the allowable and design compressive strength using L = 5m (A = 6,265mm2, rx = 106.43mm, ry = 49.28mm %3D %3D W10× 33 L A992 steelA cantilever beam with a ‘T’ shaped cross-section is loaded with a distributed load as shown below.The intensity of the distributed load is 100N/mm. b = 6.25mm and c=6.25mm.Parameter Description Value UnitsL - Beam length 250 mma - Width of the flange 80 mmd - Height of the web 75 mmσ - Yield stress 250 MPaYou are tasked with ensuring the beam can withstand the applied loading. To do this you must:a) Calculate the centroid for the given cross-section. Your value of ?ത should be measured fromthe bottom of the section. Determine an expression for Q (statical moment of area) for thegiven shape. The expression(s) for Q should be in terms of the variable, y, measured from thebottom of the section. b) Create a graph of the shear and bending stresses at the fixed support (B) over the crosssection. The stresses should be plotted as a function of y, measured from the bottom of thesection.The working load P on the propped cantilever shown are each 150 kN. If the yield stress of mild steel is 300 MPa, determine the plastic section modulus in cubic millimeters, using a load factor of 1.75 against collapse. (express your response this way, x,xxX,XXX.X). Pu Pu 1.1 2m B A 2m 2m
- dont use old content please Find the dangerous cross-section of the beam of circular cross-section which is loaded as shown in the figure below, strength via the criterion of maximum Shear stress, if yield stress equals 240 MPa, and required safety factor [k)= 2.3. Check the T= 42 KN m l= 1.8m 2= 34 KN/m a= 0.7m F: 30KN*4-36. The composite bar consists of a 20-mm-diameter A-36 steel segment AB and 50-mm-diameter red brass C83400 end segments DA and CB. Determine the average normal stress in each segment due to the applied load. Esteel l = 200 x10 Pa. EBrass = 101 K109h. |-250 mm-- 500 mm -250 mm- 50 mm 20 mm 75 kN 100 kN D A 75 kN 100 kN В Ca square composite column 500 x 500mm has the ff properties: f'c = 20.7Mpa Ast=8-20mm longitudinal bars fyt = 276Mpa I-beam W14x48 properties ASS= 3100mm^2 Fys = 250Mpa What is the ultimate axial load the column can carry Select the correct response: Pu= 3756.4 KN Pu= 4334.3KN Pu: = 5201.2KN Pu= 5779.1 KN
- An S 380 x 74 section is used as a simply supported beam to carry the uniformly distributed load of magnitude 3W and the concentrated load W. What is the maximum allowable value of W if the working stress in bending is 120 MPa?Design the simply supported beam shown in the Figure 1 for flexure Consider the following data. Characteristic compressive strength of concrete, fck= 25 N/mm? %3D Characteristic tensile strength of steel, fyk = 500 N/mm? Effective cover to reinforcement is 30 mm Density of Block work = 20 kN/m3 Draw the cross section of the beam at the mid span Height of 200 mm thick wall above the beam is 4 m 200 mm - Imposed Load-20kN/m 600 mm - 6 m(1) Redo the following Calculate Mn ? = 448 14" 21" 3' wh Beam sections, to fé= 4 ksi Grade Co steel NWC M=110** for the all questions. (a) Computer the bending stresses in beam by using transformed-area for the all question the -area method.
- Determine the load capacity of the angle ASD. USE NSCP 2015.Wed 20 Apr 45% Stresses in Beams part 5 thi qar (5 of 6) Second Class Lecturer: Dr. Ali Al Asadi Example 3: The beam shown below has a cross section of channel shape with width b=300 mm and height h=80 mm, the web thickness is t=12 mm. Determine the maximum tensile and compressive stresses in the beam due to uniform load. 300mm 3.2 KN / m 80 mm -12 mm 3 m 1.5 m 14.4 KN EM, =0 B,x3-14.4x2.25=0 B=10.8 KN B F = 0 A A,+10.8-14.4=0Using the stress block, determine the ultimate moment of resistance of the section shown in Figure 2 and check whether the steei provided satisfies the bending moment due to the loads on the beam. Characteristic compressive strength of concrete, fck= 25 N/mm² Characteristic tensile strength of steel, fyk = 500 N/mm2 Clear cover to main steel as 20 mm. Ultimate Design Load =13 kN/m 2 402 mm 370 mm 2 1470 mm 9 m 230 mm Figure 2