# 1) Use Newton's Second Law Analysis to solve the following problem. +y 1-sketch and FBDS, 2-write Ө down force equations in all dimensions, and 3 solve for requested variable. Two boxes, connected by a rope, are at equilibrium (need to consider friction on the incline). Box B is not touching the incline, it is just hanging from the outer rim of the pulley. Assume the magnitude of the tension force is greater than the magnitude of the wx component of mass A for part A (this should help you determine the direction of the static friction force). Draw the FBD for both box A and box B separately. Use N, for Normal Force, use fs for the static friction force, use proper variations of wx and wy for the weight components (two masses here, so they should have different labels not just wx and Wy for both, you need to be able to tell them apart), and use T for the Tension Force. Somewhere in your work show what your variations of the magnitudes of wx and wy are in terms of the masses and g and appropriate trigonometric terms like sine, cosine, and tangent (the problem should not have m's or w's as you have MA and mB in the problem). Assume no torques are present in the system, that is treat the masses as point masses. The rope and pulleys are massless and the pulley has no friction. Use the provided coordinate system. A (A) Find an algebraic expression for the coefficient of friction between a box A and the surface of incline when two bodies are equilibrium. Your expression must contain mo, mA, g, and 8 (of course trig term that contain 8 such as sin (0) and cos(9), if used properly, are allowed). Tension, T, is not an allowed variable in your expression for us. (B) Now let us assume the system starts to move at a non-constant velocity. Mass B starts to move down and the mass A starts to move up the incline. Now there is kinetic friction, fk. Think about what changes on your FBD. Find an expression for the tension in the rope in this situation. Your expression must only contain MB, MA, G, Hk and 8 (of course trig anomic expressions that contain e such as sin(0) and cos(8), if used properly, are allowed). The acceleration is not an allowed variable in your expression for tension.
# 1) Use Newton's Second Law Analysis to solve the following problem. +y 1-sketch and FBDS, 2-write Ө down force equations in all dimensions, and 3 solve for requested variable. Two boxes, connected by a rope, are at equilibrium (need to consider friction on the incline). Box B is not touching the incline, it is just hanging from the outer rim of the pulley. Assume the magnitude of the tension force is greater than the magnitude of the wx component of mass A for part A (this should help you determine the direction of the static friction force). Draw the FBD for both box A and box B separately. Use N, for Normal Force, use fs for the static friction force, use proper variations of wx and wy for the weight components (two masses here, so they should have different labels not just wx and Wy for both, you need to be able to tell them apart), and use T for the Tension Force. Somewhere in your work show what your variations of the magnitudes of wx and wy are in terms of the masses and g and appropriate trigonometric terms like sine, cosine, and tangent (the problem should not have m's or w's as you have MA and mB in the problem). Assume no torques are present in the system, that is treat the masses as point masses. The rope and pulleys are massless and the pulley has no friction. Use the provided coordinate system. A (A) Find an algebraic expression for the coefficient of friction between a box A and the surface of incline when two bodies are equilibrium. Your expression must contain mo, mA, g, and 8 (of course trig term that contain 8 such as sin (0) and cos(9), if used properly, are allowed). Tension, T, is not an allowed variable in your expression for us. (B) Now let us assume the system starts to move at a non-constant velocity. Mass B starts to move down and the mass A starts to move up the incline. Now there is kinetic friction, fk. Think about what changes on your FBD. Find an expression for the tension in the rope in this situation. Your expression must only contain MB, MA, G, Hk and 8 (of course trig anomic expressions that contain e such as sin(0) and cos(8), if used properly, are allowed). The acceleration is not an allowed variable in your expression for tension.
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Transcribed Image Text:#1) Use Newton's Second Law Analysis to solve the
following problem.
, 1 - sketch and FBDs, 2 - write
0
down force equations in all dimensions, and 3 solve
for requested variable. Two boxes, connected by a
rope, are at equilibrium (need to consider friction
on the incline). Box B is not touching the incline, it is
just hanging from the outer rim of the pulley.
Assume the magnitude of the tension force is
greater than the magnitude of the wx component of mass A for part A (this should help you determine
the direction of the static friction force). Draw the FBD for both box A and box B separately. Use N, for
Normal Force, use fs for the static friction force, use proper variations of wx and wy for the weight
components (two masses here, so they should have different labels not just wx and wy for both, you
need to be able to tell them apart), and use T for the Tension Force. Somewhere in your work show
what your variations of the magnitudes of wx and wy are in terms of the masses and g and appropriate
trigonometric terms like sine, cosine, and tangent (the problem should not have m's or w's as you have
mA and me in the problem). Assume no torques are present in the system, that is treat the masses as
point masses. The rope and pulleys are massless and the pulley has no friction. Use the provided
coordinate system.
B
(A) Find an algebraic expression for the coefficient of friction between a box A and the surface of
incline when two bodies are equilibrium. Your expression must contain mo, mA, g, and 0 (of
course trig term that contain such as sin (0) and cos(8), if used properly, are allowed). Tension,
T, is not an allowed variable in your expression for us.
(B) Now let us assume the system starts to move at a non-constant velocity. Mass B starts to move
down and the mass A starts to move up the incline. Now there is kinetic friction, fk. Think about
what changes on your FBD. Find an expression for the tension in the rope in this situation. Your
expression must only contain me, mA, g, Hk and 8 (of course trig anomic expressions that contain
e such as sin (0) and cos (0), if used properly, are allowed). The acceleration is not an allowed
variable in your expression for tension.
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