1- A pipeline (pipeline(a)) has initially the segments listed in Table1.1. It is compared to three other pipelines; Pipeline(b), Pipeline(c) and Pipeline(d). Find each pipeline clock cycle time in nano seconds (ns), the total executing time for the indicated n tasks and the speed up ratio; (nk)/(n+k-1). Complete Table.1.2 Table1.1 segments Segt. I Segt.2 Segt.3 Segt.4 Segt.5 tl 12 t3 14 15 time in ns 90, 70, 80, 90, 50, tasks (n) 340, Pipeline(a) uses the original segments shown in Table1.1. a- b- Pipeline(b) is the same as pipeline (a) with t4 split into 3 identical segments. C- Pipeline(c) is the same as pipeline (a) with t2 and t3 combined into one segment. -p Pipeline(d) is the same as pipeline (a) with t4 split into 3 identical segments while t2 and t3 are combined into one segment, Table 1.2 All values of time are nano second (ns) Pipeline Number of Clock cycle Pipeline total execution Non-pipeline total execution time in ns Pipeline speed-up ratio Name Segments in ns time in ns Pipeline(a) Pipeline(b) Pipeline(c) Pipeline(d)

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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1- A pipeline (pipeline(a)) has initially the segments listed in Table1.1. It is compared to three other pipelines; Pipeline(b), Pipeline(c) and Pipeline(d).
Find each pipeline clock cycle time in nano seconds (ns), the total executing time for the indicated n tasks and the speed up ratio; (nk)/(n+k-1).
Complete Table.1.2
Table1.1
Segt.2
12
Segt.3
segments
Segt. 1
Segt.4
Segt.5
15
tl
13
t4
time in ns
tasks (n)
Pipeline(a) uses the original segments shown in Table1.1.
Pipeline(b) is the same as pipeline (a) with t4 split into 3 identical segments.
Pipeline(c) is the same as pipeline (a) with t2 and t3 combined into one segment.
Pipeline(d) is the same as pipeline (a) with t4 split into 3 identical segments while t2 and t3 are combined into one segment.
90,
340,
70,
80,
90,
50,
a-
b-
C-
d-
Table1.2 All values of time are nano second (ns)
Pipeline
Name
Pipeline(a)
Pipeline(b)
Pipeline(c)
Pipeline(d)
Number of Clock cycle
Segments in ns
Pipeline
speed-up ratio
Pipeline total execution Non-pipeline total
time in ns
execution time in ns
Transcribed Image Text:1- A pipeline (pipeline(a)) has initially the segments listed in Table1.1. It is compared to three other pipelines; Pipeline(b), Pipeline(c) and Pipeline(d). Find each pipeline clock cycle time in nano seconds (ns), the total executing time for the indicated n tasks and the speed up ratio; (nk)/(n+k-1). Complete Table.1.2 Table1.1 Segt.2 12 Segt.3 segments Segt. 1 Segt.4 Segt.5 15 tl 13 t4 time in ns tasks (n) Pipeline(a) uses the original segments shown in Table1.1. Pipeline(b) is the same as pipeline (a) with t4 split into 3 identical segments. Pipeline(c) is the same as pipeline (a) with t2 and t3 combined into one segment. Pipeline(d) is the same as pipeline (a) with t4 split into 3 identical segments while t2 and t3 are combined into one segment. 90, 340, 70, 80, 90, 50, a- b- C- d- Table1.2 All values of time are nano second (ns) Pipeline Name Pipeline(a) Pipeline(b) Pipeline(c) Pipeline(d) Number of Clock cycle Segments in ns Pipeline speed-up ratio Pipeline total execution Non-pipeline total time in ns execution time in ns
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