1- 160.0 mL of 0.25 M HF with 230.0 mL of 0.31 M NaF Ka(HF)=6.8×1O^-4 Express your answer using two decimal places. pH = ? Please solve it asap...

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.22QAP
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1-
160.0 mL of 0.25 M HF with 230.0 mL of
0.31 M NaF
Ka(HF)=6.8×1O^-4
Express your answer using two decimal
places.
pH = ?
Please solve it asap...
Transcribed Image Text:1- 160.0 mL of 0.25 M HF with 230.0 mL of 0.31 M NaF Ka(HF)=6.8×1O^-4 Express your answer using two decimal places. pH = ? Please solve it asap...
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