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- For the given IP address 196.62.146.174/27, answer the following questions: a. Subnet Mask b. Number of Subnets c. Block-size for the subnet mask d. Valid Subnets e. Total Hosts f. Valid Hosts per subnetQuestion 5 What is the range of host loopback addresses in IPV6? The prefix in compressed format is [1] and the prefix length is [2] bits. Specified Answer for: 1 Specified Answer for: 2For the following Ips, write the network name, BC address, Prefix length, and thedefault maskNet name BC Prefix length default mask 11.45.3.5 180.90.27.89 190.35.177.98 192.76.19.1 200.30.50.90 100.100.100.100 107.39.50.20 192.3.5.6
- Given the IP address 137.122.91.160 and the subnet mask 255.255.248.0, what is the subnet address to which the IP address belongs? 137.122.90.248 137.122.88.0 137.122.91.160 137.122.92.248 137.122.91.0An IPv4 packet has arrived with the first few hexadecimal digits as shown. 0x47000032000100000406 . . . How many hops can this packet travel before being dropped? How many bytes of data and options are being carried by this packet?- For the given IP address 196.62.146.174/25, answer the following questions: Subnet Mask Number of Subnets Block-size for the subnet mask Valid Subnets Total Hosts Valid Hosts per subnet Broadcast address of each subnet Network address of each subnet
- Provide short answers to the following: How do you determine whether an IP address is a multicast address? What is the TTL field in the IP header used for? What is the maximum length of options bytes that can be carried in an IPv4 header? Why do we have to multiply the offset field of an IP datagram by eight to obtain the real offset for the first byte of the datagram?What is the sub-network address if the destination address is 200.45.34.56 and the subnet mask is 255.255.240.0?Given, a network address of 161.0.0.0/10. Using the figure above and by applying VLSM technique, find the network address of the subnets A, B and C. Where Subnet A has 2788 hosts, Subnet B has 484 hosts and Subnet C is the switched network interconnecting the routers. Upload Picture Please
- A standard IPV4 datagram with an initial total length 36.253 bytes reaches a router that has an MTU - 684 bytes. • The total number of fragments is • The offset of the second fragment is • The offset of the last fragment is • The number of bytes in the last fragment isGiven, a global prefix of (3651::) and a subnet ID of (1011) Find/Calculate the fully expanded IPv6 Address of the PC with MAC of 4a:ad:33:23:c2:83 Answering notation: Separate each block of the IPv6 by using a colon (:) with all lowercase letters