0 r = D cos (0)
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- Vr A camera tracks the position of a particle moving along the given path with b = 10 m. At the moment shown, the camera angle is 0 = 40°, and the camera is rotating at 0.3 rad/s, which is accelerating at a rate 0 = 0.2 rad/s². What are the radial and transverse components of velocity and acceleration at this instant? Vo = Ar 0 ao = r = b sin(20) m/s m/s m/s² m/s² =The figure shows a right-angled construction frame ABC. When measured at rest, it has dimensions as follows: AB = 18.9 m, AC = 10.0 m, and BC = 16.0 m. This frame is now given a new velocity of 0.420 c, relative to Earth, in a direction parallel to AC. How long is part BC of this frame with the new velocity as measured by Earth-based engineers?A Ferris wheel with radius 30 ft is decelerating such that at t = 0 s, the tangential speed of a point P on the rim is v=10ft/s and dv/dt = ct. c=-0.4ft/s^3 . What is the acceleration of P at t= 3 s?
- As shown in the figure. A plot of potential energy U versus position x of a 2 kg particle that can move along x-axis. The graph has these values U_A=9J, U_C=20J and U_D=24J. The particle is released at position x=5 m with kinetic energy 4 J where the potential energy is U_B=12 j. What is the kinetic energy of the particle at x =3.5 m. Upt ... Uc UAF-- 4 6 7 x (m) A) 8J B none of them C 7J D 7.5JDYNAMICS Question 2: While the car in the figure is standing at point A above, it moves downward with a = 0.981-0.013v ^ 2 m / s ^ 2 acceleration. Find Vb, which is the velocity in the existence of point B. The unit of speed is m / s. Please be careful, thank you.Given: A boat travels around a circular path, p= 40 m, at a speed that increases with time, v = (0.0625 t2) m/s. v30.06252 40 m Find: The magnitudes of the boat's velocity and acceleration at the instant t = 10 s.
- A motorcycle cage has a curved path in the x-z plane as shown. The cage path has different curved profile, and between point o and A the path is best described as z = f(x) = ax², where a = 0.09 and b = 1.23. The motorcyclist at point M is moving at a velocity of 12.6 m/s which is increasing at a rate of 1.9 m/s?. If the horizontal position of the motorcyclist at point M is xM = 11.9 m, determine (i) the direction of the motorcyclisť's velocity. (ii) the radius of the curvature of the cage's path at point M, (iii) the normal acceleration at point M, (iv) the magnitude and direction of the motorcyclist's acceleration at point M. A (z = ax4 Problem Consider two cars A and B moving at constant speeds VA = 60 kph and VB = 80 kph. Car A is traveling along a circular road that has radius r = 300 meters and is at an angle of 0 = 45 deg relative to car B. Car B is traveling westbound along a straight line. A VA r UB A B Determine a symbolic expression for (a) the relative velocity vector A/B using the unit vectors of a polar reference frame defined at point B, (b) the angular rate è, and (c) the radial rate r. Numerically evaluate your expressions for and r. (Hint: Begin by expression both VA/O and VB/O in terms of polar frame unit vectors.)Use the formula x=1/32v² sin 2 theta to explain why the projection angle that maximizes the distance a projectile traves is theta=45° when ho=0. Find the horizontal distance traveled by a football kicked from ground level (ho=0) at speed v and angle theta.
- 2.) A meteor is about to hit a planet and its velocity is defined by v = 5t4 – 5t", where t is in seconds. Find the displacement and acceleration after 5 seconds.A bullet spins as the shot is fired from a gun. For this purpose, two helical slots as shown in the figure are cut in the barrel. Projections A and B on the bullet engage in each of the slots. Gun Barrel 0.5 m 1 A B Bullet Helical slots are such that one turn of helix is completed over distance of 0.5 m. If velocity of bullet when it exits the barrel is 20 m/s, its spinning speed in rad/s is_1) Most of us rode bikes a kid. Did you ever accidentally apply the front brake while riding down a hill and flip over your handlebars? Let's analyze the level of deceleration needed to cause this to happen (at this instant the normal force of the rear tire is zero). Assume the rider is moving down a hill at a constant velocity and att = 0, the rider squeezes the brakes and begins to decelerate. This action results in a force that points in the bi direction and passes through the contact points between the tires and the pavement. Be sure to include your FBD, IRD, and transformation array. b2 30 in. FB 13 in. 23 in.