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(0) Find U. 20) The magnitude of the vector xu is the Same as the area of the parallelogram with sides and ū ("spanned on J₁). This is because say J is the base, then I sina height the -Same J=<6,0, 2√5> of the parallelogram. v² =<4₂0,0>. a) Find luxul b) Find the area of the parallelogram spanned on J, V. ✓h=julsing T

(0) Find U. 20) The magnitude of the vector xu is the Same as the area of the parallelogram with sides and ū ("spanned on J₁). This is because say J is the base, then I sina height the -Same J=<6,0, 2√5> of the parallelogram. v² =<4₂0,0>. a) Find luxul b) Find the area of the parallelogram spanned on J, V. ✓h=julsing T

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.2: The Law Of Cosines
Problem 47E
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only do 20a and 20b

19) U² = < 6, 0₁ 2√3 > V² = < 4,0,0 > a) use a suitable right triangle to kind I between I and P. the angle b) Find Div using the formula 10²||| Cos C) Find J. V using vive tų y + z vz Same 20) The magnitude of the vector JXV is the as the area of the parallelogram with sides and ū ("spanned on 3,²). This is J because say is the base, then INI sine of the parallelogramo is the height Same J = <0, 0, 2√5> V² =< 4,0,0>. J a) Find luxV²L. b) Find the area of the parallelogram spanned on J, J. Bot h=|u|sine 21) An 18-1b weight is suspended at a point On on the picture. a bent wire, as shown (The weight is attached firm by and cannot Slide at P.) use a 20 coordinate system The Force vector w pointing directly down, Shown, applied at P. a R horizontal 18 16 دن is 21'5 problems are on back
Transcribed Image Text:19) U² = < 6, 0₁ 2√3 > V² = < 4,0,0 > a) use a suitable right triangle to kind I between I and P. the angle b) Find Div using the formula 10²||| Cos C) Find J. V using vive tų y + z vz Same 20) The magnitude of the vector JXV is the as the area of the parallelogram with sides and ū ("spanned on 3,²). This is J because say is the base, then INI sine of the parallelogramo is the height Same J = <0, 0, 2√5> V² =< 4,0,0>. J a) Find luxV²L. b) Find the area of the parallelogram spanned on J, J. Bot h=|u|sine 21) An 18-1b weight is suspended at a point On on the picture. a bent wire, as shown (The weight is attached firm by and cannot Slide at P.) use a 20 coordinate system The Force vector w pointing directly down, Shown, applied at P. a R horizontal 18 16 دن is 21'5 problems are on back
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