Wilkins, a Zurn Company: Demand Forecasting

The critical value for for this two-tailed test is. The rejection region is given by

From the above output, we can see that the p-value is 0.000186, which is smaller than 0.05 (if we select a 0.05 significance level).

15 In testing the hypotheses: H0 β1 ’ 0: vs. H1: β 1 ≠ 0 , the following statistics are available: n = 10, b0 = 1.8, b1 = 2.45, and Sb1= 1.20. The value of the test statistic is:

We reject Ho if χ2 > χα2. At α=0.05, with 4 degrees of freedom, the critical value becomes χα2=9.488 (table E.4)

The null hypothesis is rejected since the p-value is below the significance level of 0.05.

In this study, t= -3.15 describes the mental health variable. It is significant because they are the variables being tested since the p value is 0.002 and the alpha is 0.05, the difference can cause the null hypothesis to be rejected.

Consider the following scenario in answering questions 5 through 7. In an article appearing in Today’s Health a writer states that the average number of calories in a serving of popcorn is 75. To determine if the average number of calories in a serving of popcorn is different from 75, a nutritionist selected a random sample of 20 servings of popcorn and computed the sample mean number of calories per serving to be 78 with a sample standard deviation of 7.

One-sample t-test are used in the parametric test which analyzes the means of populations. The t-test for independent groups are statistics that relates difference between treatment means to the amount of variability expected between any two samples of data within the same population (Hansen & Myers, 2012). Critical values are used in significant testing provide a range of t distribution that is used in whether a null hypothesis is rejected. Based on the data below as the level of significance is at .05, thus the critical values would fall under ±1.860 and the t value for this is 1.871 would suggest for the null to be rejected as it is greater than the critical value (Privitera, 2015, p. 267). Based on the population mean of 70 there was a mean difference of

The next table shows the results of this independent t-test. At the .05 significance level, can we conclude

H0: μ ≥ 3200 against H1: μ < -1.7823 when I rejected the null hypothesis.

located down the row of the t-table. The critical value result is the point where the a-level and degrees of

Since 3.27 the t statistic is in the rejection area to the right of =1.701, the level of

5) From calculations, computed z value is more than -1.65 and falls within Ho not rejected region. Ho is not rejected at α = 0.05 &amp; α = 0.01 significance levels.

There are two hypotheses that were tested in relation to the overall fit of the model:

The result of heteroskedasticity test done for Model II is also shown in Table 5.13 below. The null hypothesis of no heteroskedasticity cannot be rejected this time too. That means the standard errors, T-statistics and F-statistics done for the model are valid.