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Unknown White Compound Lab Report

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What Is The Unknown White Compound By Alexander Medina Lab Partners Maxwell Yurs, Eugene Floersch, Mesih Harri Abstract A white compound is found, but its identity is unknown. In order to properly dispose of this unknown substance, several tests needed to be performed in order to identify the substance. A flame test, pH test, and conductivity test are used to narrow the identity of the compound. After identifying the compound, its identity needs to be proven by a flame test, pH test, and conductivity test. Afterword, one gram of the unknown compound needs to be synthesized. It was determined that the most likely identity for the unknown compound was either Ca(NO3)2, CaCl2, or CaCO3. After redoing the flame …show more content…

Gather 0.61 grams of CaCO3 and 0.768 grams of HNO3, a 250 mL beaker, distilled water, and a heating pad. Put the compounds into the 250 mL beaker and add distilled water. Stir until the compounds are dissolved in the water. After the reaction is done, place the beaker onto a heating pad to evaporate the water. Scrape the remaining compound out of the beaker and mass it. Determine the percent yield. Preform a flame test, pH test, and a conductivity test to determine if the made compound is Ca(NO3)2. Results Flame test: The flame test had a variety of results. Most of the known compounds did not match our unknown except for Ca(NO3)2. Both Ca(NO3)2 and the unknown compound had a deep red/orange color flame. While Ca(NO3)2 had the closest results two other compounds had slightly different results but not different enough to rule them out. Those other two compounds were CaCl2 with a yellow/ orange color and CaCO3 with a reddish color. Since NaCL, KCl, and MgCl2 are not even close to the color of the unknown, these three compounds can be eliminated from the list of the possible identity of the unknown compound. Compound Color of flame unknown Deep red/ …show more content…

If solid CaCO3 is combined with an aqueous solution of HNO3, Ca(NO3)2 as well as CO2 and H2O will form. The chemical equation for this reaction is CaCO3 (s) + 2 HNO3 (aq) → Ca(NO3)2 (aq) + CO2 (g) + H2O (l). To theoretically make one gram of Ca(NO3)2, 0.61 grams of CaCO3 need to be added with 0.768 grams of HNO3. Adding this two compounds will release CO2 gas into the air and will also from H2O to our compound. To get rid of the water and crystalize our compound, heat the beaker with the solution on a heating plate to evaporate the H2O. After letting the compound cool down, scape it onto a piece of paper and measure it’s mass. The mass of the compound was 0.806 grams. This means that there was a percent yield of 80.6%. Looking at the table it appears that the synthesized compound is Ca(NO3)2. The synthesized compound has the same color for the flame test, the same pH level, and the mean value from the conductivity test was extremely

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