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M & M Project Essay

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Abstract The purpose of this paper is to provide a written report of the five part M&M project. Part one was sampling. We were to purchase 3 bags of M&M and record the color counts of each bag in an Excel spread sheet. For part two we calculated the sample proportions for each color, the mean number of candies per1.69oz bag, created a histogram for the number of candies per bag, use Excel to compute the descriptive statistics for the total number of candies per bag and summarize the information. In part three we located the 95% confidence interval for the proportion of blue, orange, green, yellow, red and brown. For part four we tested claims for percentages of each color. In the final part of the project we tested the hypothesis …show more content…

The results are as follows:
Sample proportions: blue=.2366, orange= .2099, green= .1702, yellow= .1428, red= .1156, brown= .1249; the histogram is skewed left
Mean= 55.5667; standard deviation= 2.0003; total # of candies=5001; # of bags= 90
The standard deviation indicates that the difference between the actual number of M&Ms per bag and the mean number of M&Ms per bag is 2.0003.

Part 3: Method, Analysis, Results The objective of this part of the project is was to construct a 95% confidence interval for the proportions of blue, orange, green, yellow, red and brown m&ms. The results were:

Blue (.22477, .24833) Orange (.19867, .22125) Green (.15975, .18058) Yellow (.13308, .15247) Red (.10672, .12444) Brown (.11581, .13414) Mean (55.153338, 55.979862 Bonus 438

Part 4: Method, Analysis, Results For this portion we were to tests Masterfoods’ claims about which proportion of colors the greatest number of people found attractive.
Blue; H0: p=.24 claim, H1: p[pic] .24; Z= -.5630, Fail to reject
There is insufficient evidence to suggest the true proportion is not .24.

Orange; H0: p=.20 claim, H1: p[pic].20; Z= 1.75; Fail to reject
There is insufficient evidence to suggest the true proportion is not .20.

Green; H0: p=.16 claim, H1: p[pic] .16; Z= 1.9676; reject
There is sufficient evidence to suggest the true proportion is not .16.

Yellow; H0: p=.14 claim, H1: p[pic] .14;

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