Elementary Statistics iLab Week 6
Statistical Concepts: * Data Simulation * Discrete Probability Distribution * Confidence Intervals
Calculations for a set of variables
Mean Median
3.2 3.5
4.5 5.0
3.7 4.0
3.7 3.0
3.1 3.5
3.6 3.5
3.1 3.0
3.6 3.0
3.8 4.0
2.6 2.0
4.3 4.0
3.5 3.5
3.3 3.5
4.1 4.5
4.2 5.0
2.9 2.5
3.5 4.0
3.7 3.5
3.5 3.0
3.3 4.0
Calculating Descriptive Statistics
Descriptive Statistics: Mean, Median
Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 Maximum
Mean 20 0 3.560 0.106 0.476 2.600 3.225 3.550 3.775 4.500
Median 20 0 3.600 0.169 0.754 2.000 3.000 3.500 4.000 5.000
Calculating Confidence Intervals for
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The mean for the column “mean” is 3.56. It is very close to the parameter of interest but is not equal to it. You can calculate a confidence interval for the mean of the mean column, but a specific confidence interval would need to be provided. In that case, the confidence interval would be centered on 3.56, not 3.5. |
4. Give the mean for the median column of the Worksheet. Is this estimate centered about the parameter of interest (the parameter of interest is the answer for the mean in question 2)
The mean for the median column is 3.6, which is close to the mean in question 2 but not as close as the answer in question 3. |
5. Give the standard deviation for the mean and median column. Compare these and be sure to identify which has the least variability?
Standard Deviation of Mean= 0.4762Standard Deviation of Median= 0.7539The standard deviation of the Mean is smaller, which means all of the data points will tend to be very close to the Mean. The Median with a larger Standard Deviation will tend to have data points spread out over a large range of values. Since the Mean has the smaller value of the Standard Deviations, it has the least variability. |
6. Based on questions 3, 4, and 5 is the mean or median a better estimate for the parameter of interest? Explain your reasoning.
The Mean seems to be the better estimate as
For the education data, I must say to calculate the median, from high school to college graduate, the median would be the some college portion since it would be the middle. The median for the experimental group would be 11 and 34.4% and for the control group it would be 15 and 41.7%.
For the education data, I must say to calculate the median, from high school to college graduate, the median would be the some college portion since it would be the middle. The median for the experimental group would be 11 and 34.4% and for the control group it would be 15 and 41.7%.
Calculate the mean, the median, and the mode for each of the following data sets:
6. To calculate Q1 and Q3 , you must first arrange the observations in increasing order to find the median, Q1 is the median of the observations whose position in the list is to the left of the overall median, Q3 is the median of the observations whose position in the list is to the right of the overall median.
The median is the midpoint of all variables in an observation that are organized from “smallest to largest” (110). In a situation where the median
Final Exam Review Questions Solutions Guide You will probably want to PRINT THIS so you can carefully check your answers. Be sure to ask your instructor if you have questions about any of the solutions given below. 1. Explain the difference between a population and a sample. In which of these is it important to distinguish between the two in order to use the correct formula? mean; median; mode; range; quartiles; variance; standard deviation. Solution: A sample is a subset of a population. A population consists of every member of a particular group of interest. The variance and the standard deviation require that we know whether we have a sample or a population. 2. The following numbers represent the weights in pounds of six 7year old
In this project we were given the case of customer complaints that the bottles of the brand of soda produced in our company contained less than the advertised sixteen ounces of product. Our boss wants us to solve the problem at hand and has asked me to investigate. I have asked my employees to pull Thirty (30) bottles off the line at random from all the shifts at the bottling plant. The first step in solving this problem is to calculate the mean (x bar), the median (mu), and the standard deviation (s) of the sample. All of those calculations were easily computed in excel. The mean was computed by entering:
Mean, median and mode are representative values and they are important factors in statistics. As seen in
a) The standard error of the mean, S.E. = /Sqrt(n) = 40,000/Sqrt(50) = 5656.8542
“The median is the middle value of the data set. To find a median we arrange the values in ascending (or descending) order, repeating data values that appear more than once. If the number of values is odd, there is exactly one value in the middle of the list, and this value is the median. If the number of values is even, there are two values in the middle of the list, and the median is the number that lies halfway between them. For an example the list 3, 4, 6, 6, 10. The median number is 6 because 6 is the middle number in the list.” (Bennett, Briggs, & Triola, 2009, p. 146).
In ascending order, the results are: 19, 22, 23, 23, 23, 24, 27, 30, 32, 47. Because 10 is an even number, the median is the mean of the two middle numbers. The two middle numbers are 23 and 24. Therefore, the median is 23.5.
The mean for the first question, which asked if the stock area clean, was 3.22. The median was 3 and the mode was 3. The mean for the second question, which asked if the employee had a lot of supplies to gather, was 3.57. The median was 3 and the mode was 3. The mean for the third question, which asked if it was easy to find the necessary supplies, was 1.80. The median was 3 and the mode was 3.
3.3 – Calculate the mean, median, and mode of each of the following population of numbers.
0.0037 in field C. Nevertheless, similar with two other larger fields, the mean and median values are still similar with base-case value.
The median is the middle score for a set of data that has been arranged in order of magnitude. The median is less affected by outliers and skewed data