Homework 4, Newton's laws 23-24-solutions
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levesque (aml6939) – Homework 4, Newton’s laws 23-24 – tejeda – (WilkesDPHY1
1)
1
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through this homework assignment.
001(part1of2)10.0points
A book is at rest on an incline as shown
below.
A hand, in contact with the top of
the book, produces a constant force
F
hand
vertically downward.
F
hand
Book
The following figures show several attempts
at drawing free-body diagrams for the book.
Which figure has the correct directions for
each force? The magnitudes of the forces are
not necessarily drawn to scale.
1.
F
g
F
hand
F
N
F
f
2.
F
g
F
hand
F
N
F
f
3.
F
g
F
f
F
N
F
hand
4.
F
N
F
f
F
g
F
hand
5.
F
g
F
N
F
f
F
hand
6.
F
N
F
hand
F
f
F
g
7.
F
g
F
f
F
hand
F
N
levesque (aml6939) – Homework 4, Newton’s laws 23-24 – tejeda – (WilkesDPHY1
1)
2
8.
F
g
F
hand
F
f
F
N
correct
Explanation:
The normal force points perpendicular to
the surface of the inclined plane. The weight
force points down.
The
F
hand
also points
down. The friction force keeps the book from
sliding and consequently points up the incline.
002(part2of2)10.0points
For the normal force exerted on the book
by the wedge in the diagram, which force(s)
complete(s) the force
pair
for Newton’s third
law (action-reaction)?
1.
the component of gravity pointing parallel
to the surface of the incline
2.
the pull of the earth on the book
3.
the component of
F
hand
pointing perpen-
dicular to the surface of the incline
4.
the normal force exerted on the wedge by
the book
correct
5.
the pull of the book on the earth
6.
the sum of the component of gravity per-
pendicular to the surface of the incline and
the component of
F
hand
perpendicular to the
surface of the incline
7.
the component of gravity pointing per-
pendicular to the surface of the incline
Explanation:
The force that completes the third law pair
with the normal force of the wedge on the
book is the normal force of the book on the
wedge.
The “the sum of the component of gravity
perpendicular to the surface of the incline
and the component of
F
hand
perpendicular
to the surface of the incline” is equal and
opposite to the normal force, but it is not a
action-reactionpair
;
e.g.
, two forces equal and
opposite to each other.
003(part1of2)10.0points
A balloon is waiting to take off.
As seen in
the figure below, the balloon’s basket sits on
a platform which rests on the ground.
The
balloon is pulling up on the basket, but not
hard enough to lift it off the platform.
platform
basket
ground
balloon
What is the free-body diagram for the plat-
form?
Some parallel vectors are offset hori-
zontally for clarity.
1.
F
ground on plat
F
grav on plat
F
bask on plat
correct
2.
F
bal on bask
F
grav on bask
F
grav on plat
3.
F
bal on plat
F
grav on plat
4.
F
bal on plat
F
plat on ground
F
grav on plat
5.
F
plat on bask
F
plat on ground
F
grav on plat
Explanation:
levesque (aml6939) – Homework 4, Newton’s laws 23-24 – tejeda – (WilkesDPHY1
1)
3
All forces acting on the platform must be
represented. No forces acting on other objects
should be represented.
004(part2of2)10.0points
What is the free body diagram for the bas-
ket?
Again some parallel vectors are offset
horizontally for clarity.
1.
F
bal on bask
F
grav on bask
2.
F
grav on bask
F
bal on bask
F
plat on bask
correct
3.
F
bask on plat
F
bask on bal
F
grav on bask
4.
F
bask on plat
F
bask on bal
F
bal on bask
5.
F
bal on bask
F
bal on bask
F
ground on bask
Explanation:
All forces acting on the basket must be
represented. No forces acting on other objects
should be represented.
005
10.0points
You place a box weighing 214
.
7 N on an in-
clined plane that makes a 35
.
2
◦
angle with the
horizontal.
Compute the component of the gravita-
tional force acting down the inclined plane.
Answer in units of N.
Correct answer: 123
.
76 N.
Explanation:
Basicconcepts
θ
W
θ
θ
W
W
1
The component of the gravitational force
acting down the plane is the side opposite the
angle
θ
, so
W
1
=
W
sin
θ
006
10.0points
If an object is not accelerating, how many
forces act on it?
1.
2
2.
1
3.
0
4.
Unable to determine
correct
5.
3
Explanation:
If it isn’t accelerating, no net force acts
on it; you do not know how many forces are
involved.
007(part1of2)10.0points
A gust of wind blows an apple from a tree.
As the apple falls, the force of gravity on the
apple is 9.27 N downward, and the force of
the wind on the apple is 1.13 N to the right.
What is the magnitude of the net external
force on the apple?
Answer in units of N.
Correct answer: 9
.
33862 N.
Explanation:
Let :
F
y
=
-
9
.
27 N
and
F
x
= 1
.
13 N
.
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