PHY 101 Lab 2
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Date
Apr 3, 2024
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Maherdeep Chhabra 1227171454 PHY 101 Jared Washburn Lab Activity - 2 Forces.
Part 1 TITLE – Maherdeep Chhabra 1227171454 Calibrating Forces. INTRODUCTION – The force of a single object and a group of objects on a rubber band is determined in Part 1. I connected a rubber band to a Ziplock bag with a paper clip and used it to hold weights. RESULT – Number of objects used Deformation 0 3.5 cm 1 4 cm 2 4.3 cm 3 4.5 cm CONCLUSION – The rubber band's size varied as the assortment of things expanded.
Part 2 TITLE – Maherdeep Chhabra 1227171454 Force sensation. INTRODUCTION – By stretching various amounts of rubber bands to various lengths, we will be able to sense an increase in force in Part 2. RESULT – The rubber band stretched to 3.5 cm in the absence of any weight. Rubber band length raised to 4.0 cm while deformation 1 with the paint tube attached to it. Rubber band stretched to 4.3 cm when I replicated deformation 2 with the additional paint tubes, and I felt a tiny increase in force. When I added a total of 3 paint tubes, bringing the length to 4.5 cm, in order to replicate Deformation 3 with the paint tubes, I had to slightly increase the tension applied to the rubber band in order to keep it open. I discovered that when there were more suspended things, it took more work to imitate the deformation to the rubber band. CONCLUSION – The rubber band's size varied as the assortment of things expanded.
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Related Questions
The bar of negligible weight is supported by two springs
each having a stiffness 180 N/m The springs are
originally unstretched, and the force is vertical as shown (
Figure 1)
Figure
C
30 N
Im
B
2m
Part A
Determine the angle the bar makes with the horizontal, when the 30-N force is applied to the bar
Express your answer using three significant figures.
VAX
Submit
Request Amer
Return to Assignment
vec
Provide feedback
?
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What trigonometric identity may be used to summarize an equation for calculating tension force (the long equation you'll use before replacing the values)?
What do you think the role of mass is in determining the net acceleration of an item rolling down an incline? Friction is a significant factor.
Why is the normal force no longer equal to the weight of all things on an incline?
arrow_forward
1Gmail
Copy of mom it for.
Maps
Old Telephone Ima.
Preview attachmen..
Cami Uploads Sylvanus Gator - Mechanical Advantage Practice Sheet.pdf
5. *** A force of 75N is applied to a nutcracker to crack open a walnut. If the MA of the nutcracker
is 5, what is the force the nutcracker applies to the walnut?
Force =
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Q3/ In real life engineering application, it is required to design a spring in train, which one of
the following materials in the table below should be choose, justify your answer ? used correct
units?
Poisson's
Yield Strength
Modulus of Elasticity
106 psi
Material
MPа
psi
GPa
Ratio
30
0.30
120000
207
Steel alloy
Brass alloy
Aluminum alloy
Titanium alloy
830
0.34
0.33
380
55000
97
14
275
40000
69
10
690
100000
107
15.5
0.34
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A piece of steel rebar is tested in tension to determine its mechanical properties.
The length of the sample is 87.3 mm and the cross-sectional area is 52.1 mm².
When stretched by 37.2 mm, the force measured is 14,884 N. At this point, the graph is non-linear,
but no clear neck is visible.
If the Poisson's ratio of the material is 0.281, calculate the cross-sectional area (mm²) at this point.
arrow_forward
p A667849305_17711 26_2021_Ass X
O File | C:/Users/acer/Downloads/A667849305_17711_26_2021_Assignment%202%20MEC107.pdf
of 3
(D Page view A Read aloud
V Draw
E Highlight
O Erase
3
Q. 3 Determine the force in each member by using method of joint in given figure 3. State
whether each member is in tension or compression.
3 ΚΚΝ
3 ΚΝ
3 KN
D
1.5 KN
1.5 KN
3 m
B
F
3 m
H.
A
E
G
4 m
4 m
4 m
4 m
Activate Windows
Figure 3
Go to Settings to activate Windows.
12:16
O Type here to search
4») G ENG
03-04-2021
近
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Recall that muscle generates force at 30 N/cm?. Two cross sections are taken from the rectus femoris
muscle (bipennate muscle similar to the diagram below). The length and width of the first cross
section is 6 cm and 5 cm respectively with a 35° angle of pennation. The length and width of the
second cross section is 5.6 cm and 3 cm respectively with a 31° angle of pennation. What is the
predicted maximum tendon force (FTendon) of this muscle in Newtons? Answer to the nearest 0.1 N.
Freodas
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1.
1100
A.
30%
B.
1.1 m
1.0 m
A
F= 255 N
0.5 m
1.5 m
DGB
WARNING! The figure is not drawn to scale. For the force in the chain CB, ca
IMAGES NOTES DISCUSS UNITS STATS HELP
PREFERENCES
Part Description
the magnitude of component
parallel to the hinge axis of the
door,
(include units with answer)
0.5 m
Answer
118.77 N
Format Check
the magnitude of the component
parallel to the edge of the door that 218.17 N
is perpendicular to the hinge axis,
(include units with answer)
Format Check
Save
25 pts.7 75%
5% try penalty
31.67 pts.95%
5% try penalty
Status
Tr
● W
#tries:
**
Tr
• W.
#tries:
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Q2/ In the nucleus pulposus of an intervertebral disc, the compressive load is 1.5 times
the externally applied load. In the annulus fibrosus, the compressive force is 0.5 times
the external load. What are the compressive loads on the nucleus pulposus and annulus
fibrosus of the L5-S1 intervertebral disc of a 90 kg man holding a 50 kg weight bar
across his shoulders, given that 63% of body weight is distributed below the disc?
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Test Specimen
4140 CF steel
6061 T6 Al
Gray Cast iron 40
FC Brass 360
Impact Energy (J or ft-lb)
48.5 ft-lb
25 ft-lb
12 ft-lb
27 ft-lb
Impact Strength (J/m
or ft-lb/in)
123.096 ft-lb/in
63.452 ft-lb/in
What is the final analysis/ overall observation from the data?
30.457 ft-lb/in
68.528 ft-lb/in
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Determine the force (Newtons) of biceps brachii for each elbow positions given that the weight of the forearm & hands is 1.5kg at 0.15m from the elbow joint. Please show your solutions. Sample solution was provided for 30 degrees.
Elbow Angles
Horizontal Distance of the weight of forear, (dx COG in meters)
Force of Biceps Brachii
(in Newtons)
30o
dx = (sin30o)(0.15m)
dxCOG = 0.075 m
τ = (Fbiceps)(dx_biceps)+(FCOG)(dx_COG)
τ = (Fbiceps)(0.03m)+(1.5kg)(-9.8m/s2)(0.075m)
τ = equal to zero since the system is in statics
0 = (Fbiceps)(0.03m)+(1.5kg)(-9.8m/s2)(0.075m)
Fbiceps = 36.75N
60o
90o
120o
150o
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As the tempering temperature of a heat-treated steel increases, the associated values of Brinell hardness also increases, while the values of tensile strength and yield strength decrease.
True
False
The correct definition of Dimensional Analysis is:
A procedure to find the yield point of a material when no definitive yield point can be determined graphically.
A procedure to calculate the Elastic Modulus.
A procedure to verify the size of a mass of material.
A methodical process of converting from one set of units to another set of units.
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Figure
15°
700 N
1 of 1
Part A
If 0 = 54° and F = 460 N, determine the magnitude of the resultant force. (Figure 1)
Express your answer to three significant figures and include the appropriate units.
FR = 460
Submit
Part B
μA
X Incorrect; Try Again; 5 attempts remaining
Review your calculations and make sure you round to 3 significant figures in the last step.
Submit
N
Previous Answers Request Answer
= 159.74
Determine the resultant force direction, measured counterclockwise from the positive x axis.
Express your answer using three significant figures.
Provide Feedback
Avec
?
Previous Answers Request Answer
?
O
X Incorrect; Try Again; 5 attempts remaining
Review your calculations and make sure you round to 3 significant figures in the last step.
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+ Space Trusses
Learning Goal:
To analyze the forces within space truss members and
the reaction forces that act on space trusses.
A space truss is a stable three-dimensional structure
that consists of members joined at their ends. If the
external loading is applied at the joints, and the joints
are ball-and-socket connections, the members of a
enaro trice may ha traatad ac tun-force membere
Figure
0.50 m-
1.50 m
1.50 m
0.50 m
B
D
< 2 of 2
2.00 m
F
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Simple Machines-Levers, Inclined Planes, and Pulleys
Directions: Use the appropriate equation to answer the following questions. All answers should be
recorded below or in your Engineering Design journal. Remember to show all work.
A lever has an effort arm that is 5 meters long and a resistance (load) arm that is 3.5 meters
long. How much effort is needed to lift a 100 Newton weight? 5K
i). Draw the figure representing the problem
ii). How much effort is needed to lift a 100 Newton weight?
iii). What is the Actual Mechanical Advantage
1.
5m
i)
AOON 5-5m
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Learning Goal:
To use fundamental geometric and statics methods to determine the state of plane stress at the point on an element of material that is rotated clockwise through an angle from the in-
plane stress representation of the point.
The state of in-plane stress at a point on an element of material is shown. Let o,
the same point that is rotated through an angle of 0-35
45.0 ksi, o, 19.0 ksi, and Ty 12.0 kai. Use this information to represent the state of stress of
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0.4m
6.6 m
0.4m
For the above dlagram, there are smooth Journal bearings at supports A B and C. Given that
y- 1.2m force. F- 450 N (acting on the coner Jolnt between B and C and parallel to y-z
plane) and moment M- 500 Nm, calculate the following:
The magnitude of the reaction force, RCY. Please provide the answer In Newtons and report
to three significant figures. Please include the unit ("N") within your answer (e.g. If the
calculated answer was 55.562 Newtons piease Input: 55.6 N).
Answer:
The magnitude of the reaction force Rcz. Please provide the answer in klo Newtons and
report to three significant figures. Please Include the unit ("kN") within your answer (e.g. if
the calculated answer was 55.562 kilo Newtons please input: 5.6 kN).
Answer:
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Q3/ A patient who suffers from a problem in the knee joint and needs a
joint replacement. As a Biomaterials engineer, you have three metal
materials, any of these materials in the table 1. you prefer for the
replacement process with mentioning the reason. If you know that the joint
is exposed to compression resistance resulting from the weight of the
person, and the load applied on the joint is 80 kg, with a cross-sectional
area of 40 mm
Table 1. The materials properties
Materials
Compressive strength (Mpa)
Туре I
17.6
Туре II
30.2
Туре I
6.5
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Determine the tension developed in the cable AC required to support the traffic light
Express your answer to three significant figures and include the appropriate units.
HA
?
FAC =
Value
Units
Submit
Request Answer
Part C
Figure
1 of 1
Determine the tension developed in the cable AD required to support the traffic light
Express your answer to three significant figures and include the appropriate units.
6 m
?
HA
3 m
FAD =
Value
Units
4 m
4 m
Submit
Request Answer
3 m
4 m
6 m
4 m
3 m
y
Provide Feedback
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SEE MORE QUESTIONS
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Related Questions
- The bar of negligible weight is supported by two springs each having a stiffness 180 N/m The springs are originally unstretched, and the force is vertical as shown ( Figure 1) Figure C 30 N Im B 2m Part A Determine the angle the bar makes with the horizontal, when the 30-N force is applied to the bar Express your answer using three significant figures. VAX Submit Request Amer Return to Assignment vec Provide feedback ?arrow_forwardWhat trigonometric identity may be used to summarize an equation for calculating tension force (the long equation you'll use before replacing the values)? What do you think the role of mass is in determining the net acceleration of an item rolling down an incline? Friction is a significant factor. Why is the normal force no longer equal to the weight of all things on an incline?arrow_forward1Gmail Copy of mom it for. Maps Old Telephone Ima. Preview attachmen.. Cami Uploads Sylvanus Gator - Mechanical Advantage Practice Sheet.pdf 5. *** A force of 75N is applied to a nutcracker to crack open a walnut. If the MA of the nutcracker is 5, what is the force the nutcracker applies to the walnut? Force =arrow_forward
- Q3/ In real life engineering application, it is required to design a spring in train, which one of the following materials in the table below should be choose, justify your answer ? used correct units? Poisson's Yield Strength Modulus of Elasticity 106 psi Material MPа psi GPa Ratio 30 0.30 120000 207 Steel alloy Brass alloy Aluminum alloy Titanium alloy 830 0.34 0.33 380 55000 97 14 275 40000 69 10 690 100000 107 15.5 0.34arrow_forwardA piece of steel rebar is tested in tension to determine its mechanical properties. The length of the sample is 87.3 mm and the cross-sectional area is 52.1 mm². When stretched by 37.2 mm, the force measured is 14,884 N. At this point, the graph is non-linear, but no clear neck is visible. If the Poisson's ratio of the material is 0.281, calculate the cross-sectional area (mm²) at this point.arrow_forwardp A667849305_17711 26_2021_Ass X O File | C:/Users/acer/Downloads/A667849305_17711_26_2021_Assignment%202%20MEC107.pdf of 3 (D Page view A Read aloud V Draw E Highlight O Erase 3 Q. 3 Determine the force in each member by using method of joint in given figure 3. State whether each member is in tension or compression. 3 ΚΚΝ 3 ΚΝ 3 KN D 1.5 KN 1.5 KN 3 m B F 3 m H. A E G 4 m 4 m 4 m 4 m Activate Windows Figure 3 Go to Settings to activate Windows. 12:16 O Type here to search 4») G ENG 03-04-2021 近arrow_forward
- Recall that muscle generates force at 30 N/cm?. Two cross sections are taken from the rectus femoris muscle (bipennate muscle similar to the diagram below). The length and width of the first cross section is 6 cm and 5 cm respectively with a 35° angle of pennation. The length and width of the second cross section is 5.6 cm and 3 cm respectively with a 31° angle of pennation. What is the predicted maximum tendon force (FTendon) of this muscle in Newtons? Answer to the nearest 0.1 N. Freodasarrow_forward1. 1100 A. 30% B. 1.1 m 1.0 m A F= 255 N 0.5 m 1.5 m DGB WARNING! The figure is not drawn to scale. For the force in the chain CB, ca IMAGES NOTES DISCUSS UNITS STATS HELP PREFERENCES Part Description the magnitude of component parallel to the hinge axis of the door, (include units with answer) 0.5 m Answer 118.77 N Format Check the magnitude of the component parallel to the edge of the door that 218.17 N is perpendicular to the hinge axis, (include units with answer) Format Check Save 25 pts.7 75% 5% try penalty 31.67 pts.95% 5% try penalty Status Tr ● W #tries: ** Tr • W. #tries:arrow_forwardQ2/ In the nucleus pulposus of an intervertebral disc, the compressive load is 1.5 times the externally applied load. In the annulus fibrosus, the compressive force is 0.5 times the external load. What are the compressive loads on the nucleus pulposus and annulus fibrosus of the L5-S1 intervertebral disc of a 90 kg man holding a 50 kg weight bar across his shoulders, given that 63% of body weight is distributed below the disc?arrow_forward
- Test Specimen 4140 CF steel 6061 T6 Al Gray Cast iron 40 FC Brass 360 Impact Energy (J or ft-lb) 48.5 ft-lb 25 ft-lb 12 ft-lb 27 ft-lb Impact Strength (J/m or ft-lb/in) 123.096 ft-lb/in 63.452 ft-lb/in What is the final analysis/ overall observation from the data? 30.457 ft-lb/in 68.528 ft-lb/inarrow_forwardDetermine the force (Newtons) of biceps brachii for each elbow positions given that the weight of the forearm & hands is 1.5kg at 0.15m from the elbow joint. Please show your solutions. Sample solution was provided for 30 degrees. Elbow Angles Horizontal Distance of the weight of forear, (dx COG in meters) Force of Biceps Brachii (in Newtons) 30o dx = (sin30o)(0.15m) dxCOG = 0.075 m τ = (Fbiceps)(dx_biceps)+(FCOG)(dx_COG) τ = (Fbiceps)(0.03m)+(1.5kg)(-9.8m/s2)(0.075m) τ = equal to zero since the system is in statics 0 = (Fbiceps)(0.03m)+(1.5kg)(-9.8m/s2)(0.075m) Fbiceps = 36.75N 60o 90o 120o 150oarrow_forwardAs the tempering temperature of a heat-treated steel increases, the associated values of Brinell hardness also increases, while the values of tensile strength and yield strength decrease. True False The correct definition of Dimensional Analysis is: A procedure to find the yield point of a material when no definitive yield point can be determined graphically. A procedure to calculate the Elastic Modulus. A procedure to verify the size of a mass of material. A methodical process of converting from one set of units to another set of units.arrow_forward
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