Investigation18_online_summer

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School

Coconino Community College *

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Course

110

Subject

Geography

Date

Apr 29, 2024

Type

pdf

Pages

4

Uploaded by EarlWildcat346 on coursehero.com

GLG 110 Natural Disasters Name: __________________________ Investigation 18 Flooding Instructions: Use the links and figures provided to answer the questions. Part 1: Streamflow 1. Recall that the discharge (Q) of a stream is calculated by the cross-section area of the stream multiplied by the velocity of the water: ࠵? = ࠵? × ࠵? Note that since the units of area (in feet) are ft 2 and the units of velocity are ft/s, the units of discharge are ft 3 /s (cubic feet per second). Stream channels usually aren’t neat boxes, so we calculate cross-section area by adding up many small rectangles instead of one big one. Calculate the discharge of the stream in the figure below. 23.3 X 2= 46.6 46.6 X .5 = 23.3 ft 3 /s 2. The average depth of the stream in the figure above is 2.59 ft, and the total width is 18 ft. After a rainstorm, assume that the discharge of this stream increases to 35 ft 3 /s at a velocity of 0.7 ft/s. a. Calculate the new average depth of the stream after the rainstorm. Average of 2.78 ft b. The stream will flood over its banks if the average depth is greater than 3 ft. Does the stream flood after this rainstorm? No because 2.78 is less than 3
3. This figure shows streamflow measurements for a river in southern Utah. ( Source link ) a. What was the approximate stream discharge for March 13 – 21? An average of 19 cubic feet of water a second. b. What was the peak stream discharge shown on the graph? On March 23 rd there was a peak of 94 cubic feet of water per second. c. What do you think happened around March 23 to increase the stream discharge? I would guess heavy rainfall produced the spike in the graph.
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