ECE310_-_2015_Final_Exam

ASAP

What will be the final value of DI after executing the following piece of code? Execute the instructions dependently one after another. CLD MOU CX,OFOH MOU AX,05678H MOU DI,01000H MOU ES, DI SUB DI, DI REPNZ SCASB -R AX-0000 DS-073F 073F:0100 0000 D 1000:0 F 1000:0000 92 00 14 12 54 56 44 78-AD 56 78 FO 00 00 00 00 BX-0000 CX-0000 DX-0000 SP-00FD ES-1000 SS%3073F CS=073F BP-0000 SI=0000 DI=0000 IP-0100 NU UP EI PL NZ NA PO NC ADD IBX SI1,AL DS:0000 CD TUDX.Ux..... .... Notes: 1- Use the DEBUG window to answer this question (values shown are prior to execution and in hexadecimal 2- Write down the final value of DI as four hexadecimal digits without any additional characters.

5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101

1.2 Convert to octal. Convert to hexadecimal. Then convert both of your answers to decimal, and verify that they are the same. 111010110001.011, (b) 10110011101.112

What will be the modified form of the following codeword is odd parity scheme is used: Codeword: 0110101

Q3/Find the solution of the following operation for octal number 717*0.33 301.05 237.05 303.25 236.61 None of them

5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (В) 55 (C) 26 (D) 34

Find the state graph for the following parallel counter: QA C clk clk clk (Handwriting solution is needed: include this in your pdf file) CBA B

please solve this accurate and exact. thank you

Digital communication system can handlea) Analog signalsb) 1D signalsc) 2D signalsd) All of the mentioned

Remember tD put no space in between characters. If the final answer is a whole number, put no decimal places. If it has one decimal place, then just put one decimal place.IF the final anser has two decimal places, then put two. A maximum of two decimal places shall be placed as final answer. Also, do not forget your units.) Given that C1= 2.5F, 02= 1.5F d3= 2F. C4= 2F. Solve for the follawing: V1 = V2 = V3 = V4 = 03 =

processors Systems And Interfacing If you subtract two decimal numbers, after BCD subtraction, to correct the result we use Oa AAA Instruction Ob AAM instruction Oc DAA instruction Od. DAS instruction Next page Windows bu alacy Jait ------ hp f3 ア D f7 19 %23 & フ R T Y Y ! VACO 12 DI F 1 G Y BY N T こo つ

Calculate circular convolution of first 4 digit and lasr 4 digit of your student number. My student number is 209106106075.

Decimal equivalent of Octal number (764), is, O 498 500 496 502

Q- DA D Find the state graph for the following parallel counter: C B clk clk clk (Handwriting solution is needed: include this in your pdf file) CBA

hi. could you solve the wuestion in pic? thank you...

Q1/The Gray code ( 10110111101)= ( ) in decimal number O 1749 O 1877 O 1750 1753 869 None of them 931 867 Q3/Find the solution of the * following operation for octal number 717*0.33

A Moving to the next question prevents changes to this answer. Question 2 To convert (11110101)2 to BCD code, how many steps you use? What are they? What is the result of conversion? (write your answer in the box below (do not include this in your pdf file)

Solve it clearly please By Computer writing

The number of possible minterms and Maxterms with a function defined on 7 variables is: 32 minterms & 64 Maxterms 128 minterms & 128 Maxterms 128 minterms & 0 Maxterms O minterms & 128 Maxterms

The logic function implemented by the multiplexer circuit is (ground implies a logic "0") 4x1 MUX 1。 1₁ 1₂ 13 S₁ S₂ P Q Y -F

The observation of a certain measurement is described by the following figure. 'True' value A Which of the following statement is correct ? O a. low accuracy and high precision O b. low accuracy and low precision Oc high accuracy and low precision O d. high accuracy and high precision

can you draw this circuit probably ,,,   draw it any program software    in print font

For the counter shown below,the sequence of counting for this counter is (in decimal): CLK PL U/D Operation Q3 Q2 QI Q0 PL D3 D2 DI DO Load UID Counts up Counts down clk 0 1 1 1 Select one: 1 2 3→4→1→2...etc O11 10 9→8→7→11.....etc 7 8 9 10→11→12→7→8.....etc 12 11 10-9→8→7→12.....etc O7 8→9→10→11→7, 8, ....etc 3 2 1 0→3.....etc 0 1 2 3→0→1...etc 3-2 1+3...etc 4 3→ 2→1→4→3.....etc Answer is not listed X个不

Perform the following conversion : A) converting (756.603)8 to hex b) converting A0F9.0EB to decimal C)(1001010)10 to gray D)(163.875)10 to binary E) 0110BCD to excess-3

Calculate the sum of series of odd numbers from the list of numbers. The length of the list is in ML 2200H and series itself begins from ML 2201H.  Assume the sum to be greater than FFH. Store the results in ML 2300H and 2301H