PERCENT YIELD LAB

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Atlantic Coast High School - Jacksonville *

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1020

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Chemistry

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May 4, 2024

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docx

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5

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Percent Yield BLAKE THOMPSON Instructions: Complete all sections of this report and answer all questions in complete sentences for full credit. Title: Percent Yield Lab Objective(s): The objective of this lab is to react magnesium metal with oxygen in the air by burning the metal and determine the percent yield of magnesium oxide (MgO). Materials: What scientific equipment and tools were used to collect data in the simulation? (Record the materials as you work through the simulation.) Materials Bunson Burner Crucible Metal Ribbon Scale Steel wool Variables: Remember the three variables: controlled (what is kept the same), independent (what is tested or changed), and dependent (what is the outcome or observed). List variables below as you work through the simulation. Type Variables Controlled Factors that remain the same throughout Independent Amount of magnesium Dependent The yield of magnesium oxide Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School.
Procedure: Clear steps are in the simulation. No written procedure is needed for this virtual experience. However, it is important that you understand the experimental design of this lab for the conclusion section. Data Type the data in the data table below. Don't forget to record measurements with the correct number of significant figures and units. Data Trial 1 Trial 2 Mass of empty crucible with lid 26.6g 26.6g Length of ribbon cut 1cm 1cm Mass of Mg metal, crucible, and lid 26.9g 26.9g Mass of MgO, crucible, and lid 27g 27g Calculations Show your calculations for each of the following. Remember, calculations should follow rules for significant figures. Remember to use the balanced chemical reaction: 2Mg (s) + O 2(g) → 2MgO (s) . 1. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of Mg, crucible, and lid (row 3 in the chart) to find the mass of magnesium for each trial. Trial 1 Mass of Mg = 26.9 g - 26.6 g = 0.3 g Trial 2: 26.9 g - 26.6 g = 0.3 g 2. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of MgO, crucible, and lid (row 4 in the chart) to find the mass of magnesium oxide for each trial. This is the actual yield of magnesium oxide for each trial. Trial 1: Mass of MgO = 27 g - 26.6 g = 0.4 g Trial 2: Mass of MgO = 27 g - 26.6 g = 0.4 g 3. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial using stoichiometry. Trial 1: Theoretical yield = 2×0.0123mol×40.30g/mol=0.987g Trial 2: Theoretical yield = Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School.
2×0.0123mol×40.30g/mol=0.987g 4. Determine the percent yield of MgO for your experiment for each trial. Trial 1: Percent yield = (0.4 g / 0.987 g) × 100% ≈ 40.5% Trial 2: Percent yield = (0.4 g / 0.987 g) × 100% ≈ 40.5% 5. Determine the average percent yield of MgO for the two trials. average percent yield ≈ (40.5% + 40.5%) / 2 ≈ 40.5% Therefore, the average percent yield of MgO for the two trials is approximately 40.5% . Conclusion Using complete sentences, write a conclusion that addresses the following: The purpose of the lab, what you explored, what you learned An explanation of how percent yield can be affected during experimentation A description of the sources of errors that impacted your data measurements Unless Otherwise Noted All Content © 2022 Florida Virtual School. FlexPoint Education Cloud™ is a trademark of Florida Virtual School.
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