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Name LS7B Week 3 Lab Worksheet You are a genetic counselor and a couple has come to you for advice. They have a family history of cancer and are concerned that their unborn third child will also get cancer. They provide you with the following pedigrees for two different traits relating to defects in the enzymes separase and topoisomerase: A. . Separase 2 3 Yugend 4 defect ; e ke s @ 0 B. () Topoisomerase 1 (2) G— defect T . . | These two pedigrees represent the same family. Genetic testing shows that individual 4 has only nonmutant alleles of both genes and individual 12 has only mutant alleles of both genes. Individuals 6, 8, 9, 12, and 14 have cancer. The couple just recently learned that their daughter (individual 14) has cancer and has both mutations. In this lab activity, you will use genetic hypothesis testing to determine the probability that the couple’s third unborn child will also inherit both mutations and be at risk for developing cancer. Part 1. Now that you’ve had some practice with using Punnett Squares in the week 2 lab and class, let’s examine the pedigrees presented above a bit further. 1. Let’s start by figuring out what kind of trait is caused by the separase mutation. Test each of the four possible hypotheses (X-linked dominant, X-linked recessive, autosomal dominant, autosomal recessive) and determine which hypothesis cannot be rejected. Write your final solution with a brief explanation. X-linked dominant is rejected because it is not possible for person 7 to be not affected X-linked recessive cannot be rejected because all females are carrier Autosomal dominant is rejected because it's not possible for both non-affected persons 3 and 4 to produce a child that is affected Autosomal recessive is rejected because person 4 has only non-mutant alleles of both which is RR; therefore, persons 3 and 4 cannot produce a child that is affected (rr)
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Related Questions
genetics question for Icke P.
Jenny, like her mother, is heterozygous for both X-linked traits. Her father suffered from bothhypophosphatemia and muscular dystrophy. Jenny’s fiancé, Mark has a mother suffering from musculardystrophy despite having normal bone conditions. His father has been blessed with strong bones andmuscles but suffered from amelogenesis imperfecta.
a. Give the complete genotypes of the following individuals:
Jenny, Jenny's mother, Jenny's father, Mark, Mark's mother, Mark's father.
b. Should Jenny and Mark eventually marry, what is the probability that they will have:
a child with muscular dystrophy, a child with amelogenesis imperfecta,
a son with hypophosphatemia, a daughter with muscular dystrophy, a child with the same genotype as Jenny, a child with the same genotype as Mark
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17. In rats, the following genotypes of two independently assorting autosomal genes determine coat color.A_B_ (gray)A_bb (yellow)aaB_ (black)aabb (cream)A third gene pair on a separate autosome determines whether or not any color will be produced.The CC and Cc genotypes allow color according to the expression of the A and B alleles.However, the cc genotype results in albino rats regardless of the A and B alleles present.
Given the inheritance pattern of coat color in rats described in Problem 17, predict the genotype and phenotype of the parents who produced the following offspring:
(c) 27/64 gray: 16/64 albino: 9/64 yellow: 9/64 black: 3/64 cream
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10)
Phenylketonuria (PKU) is a recessive disorder. Jack and Jane look normal but have a child with PKU. Therefore, what are the genotypes of Jack and Jane? __________________________________
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Practice Pedigree Problem help. I am confused so please show. Label Phenotypes and genotypes as you go about the Pedigree (and whatever else might be required)! Thank you again for your help, these questions confuse me).
Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individuals which are heterozygous for these alleles are calico or tortiseshell in color.
a). If a long-haired, black male is mated with a calico female homozygous for short hair, what kind of kittens will be produced in the F1generation? Give both genotypes and phenotypes; express the genotypes both symbolically and in words.
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Ch. 14-3
Marfan syndrome (Section 13.5) ) is inherited in an autosomal dominant pattern. What is the chance that a child will inherit the associated allele if one parent does not carry it and the other is heterozygous?
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Ch. 14-6
A mutation on an autosome causes a particular protein to be overproduced, and the excess protein accumulates in the liver and damages it. Would the resulting disorder most likely be inherited in an autosomal dominant or recessive pattern?
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Unpacking the Problem 44John and Martha are contemplating having children, butJohn’s brother has galactosemia (an autosomal recessivedisease) and Martha’s great-grandmother also had galactosemia. Martha has a sister who has three children, none ofwhom have galactosemia. What is the probability that Johnand Martha’s first child will have galactosemia?1. Can the problem be restated as a pedigree? If so, writeone.2. Can parts of the problem be restated by using Punnettsquares?3. Can parts of the problem be restated by using branchdiagrams?4. In the pedigree, identify a mating that illustratesMendel’s first law.5. Define all the scientific terms in the problem, and lookup any other terms about which you are uncertain.6. What assumptions need to be made in answering thisproblem?7. Which unmentioned family members must be considered? Why?8. What statistical rules might be relevant, and in whatsituations can they be applied? Do such situations existin this problem?9. What are two generalities…
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Need explanation on #4 of my genetic question
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Question:-
The success of renal transplantation depends on three human histocompatibility genes, HLA-A, HLA-B and HLA-C, which must match between the donor and the receiver. A single mismatch may cause the kidney rejection. Each gene has multiple co-dominant alleles. These three genes are located very close to each other on chromosome 6, so that the recombination rate is very low (below 1%).
The father has the following genotype: A1, A2, B24, B10, Cw4 and Cw7 and the mother is A1, A1, B11, B7, Cw5 and Cw8. Their first boy is A1, A1, B24, B11, Cw7 and Cw8. What is the probability that the second child is compatible with his/her brother?
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Multiple Choice
1. For double-stranded DNA, which nucleotide base pairing ratio will result to 1?
A. C/T
B. (A+T)/(G+C)
C. A/G
D. (A+C)/(G+T)
2. Why are genetic disorders such as hemophilia and Duchenne muscular dystrophy more prevalent in males than females?
A. Because they can only be passed on from father to son
B. Because they are recessive disorders
C. Because they are dominant genetic disorders
D. Because they are X-linked recessive disorders
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polygenic trait mating 2
An AaBBCcdd male mates with an AaBbCCDD female.
1. What is the maximum number of ridge-producing genes possible in one of the children?
2. What would be the TRC for this child if it is a male?
3. What is the minimum number of ridge-producing genes possible in a child of this couple?
4. If this child were a female, would she have a higher or lower TRC than the parent with the lower ridge count?
A. lower
B. higher
C. equal
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Do all of them please
Multiple choice
1) Although Dolly was only three years old, her chromosomes had the length of a (9-10)-year old sheep. Which of the following best describes why this occurred?A) The cell lines that created Dolly were aged prematurely in the labB) Nonhomologous recombinationC) A mutation enhanced the rate of agingD) Dolly was not a cloneE) The telomeres of the somatic cells that Dolly originated from were shorteningAnswer: 2) Which of the following terms represents a cell that can form any other cell of the organism?A) PluripotentB) TotipotentC) UnipotentAnswer: 3) Bone marrow transplants typically use what type of cells?A) Embryonic stem cellsB) Embryonic germ cellsC) Embryonic carcinoma cellsD) Hematopoietic stem cellsAnswer: 4) Which of the following is an example of a pluripotent cell?A) Embryonic stem cellsB) Red blood cellsC) Fetal heart cellsD) Umbilical cord bloodE) Nerve cellsAnswer: 5) An organism that has integrated recombinant DNA into its genome is…
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14. Type 1 fucosidosis is a rare human disease. Patients cannot hydrolyze the disaccharide fucose, and as a result have severe neurological decline and die by age 6. The disease is due to a defect in the gene that encodes the lysosomal enzyme that breaks down fucose (α-1-fucosidase), and is inherited in an autosomal recessive manner. Jane and John have a child who has Type 1 fucosidosis. What is the probability that their next child will also have the disease?
A. 4/4 or 100%
B. No chance
C. 3/4
D. 1/4
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21. In Mendel early experiments with heredity in peas, he discovered that some have variable colors, some yellow and some green. These variable traits are alternate versions of an _____
a. Allele
b. mDNA fragment
c. Derived trait
d. Discrete trait
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1. In this pedigree, if individual III3 mated with an unaffected male and they have 7 kids, what is the probability that their children will have cystic fibrosis?
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Genetics of man 1)Determine the sex of the individual/patient based on your karyotyping results attached below. 2)Specify what kind of disorder this individual/patient may have based on your karyotyping results attached below .
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11. Below is a pedigree chart of an autosomal recessive disorder. Answer the following questions using the correct genetic terminology (do not just write letters like “Ee”).
A. What is the genotype of individual 1 in generation II? B: What is the genotype of individual 2 in generation I?C: Is it true that individuals 6, 7, 8, 9, and 10 in generation III all have the same genotype? Why or why not?
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Ch. 14-4
Duchenne muscular dystrophy, which is inherited in an X-linked recessive pattern, nearly always occurs in males. Explain why.
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Ch. 18-2
The photos shown below illustrate a case of synpolydactyly, a genetic abnormality characterized by two phenotypes: partially or completely duplicated fingers or toes, and webbing between fingers or toes. The same mutations that give rise to the human phenotype also give rise to a similar phenotype in mice. In which family of genes do you think these mutations occur?
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Question:-
Based on your selected mode of inheritance, show the genotypes for the following individuals. [Use these symbols for alleles: if it is autosomal, then use the symbols B - dominant, b - recessive (e.g. BB, bb etc.) if it is X-Linked, then X(B) - dominant, X(b) - recessive, and Y for Y-chromosome (e.g. X(B)X(B), X(B)Y etc.) ]
I-1
I-2
II-7
II-8
III-10
III-11
III-12
IV-8
IV-9
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Question-
QUESTION 1
Consider three linked genes: A, B, C. Percent recombination between gene B and C is 11% and no crossing over occurs between A and B. If a heterozygote in cis conformation is test crossed, what is the probability of an offspring with the genotype AaBbcc?
A. 0.011
B. 0.055
C.0.022
D.0.089
E. 0.045
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Marfan syndrome (Section 13.5) is inherited in an autosomal dominant pattern. What is the chance that a child will inherit the associated allele if one parent does not carry it and the other is heterozygous?
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Karyogram and Identification of Chromosomal Aberrations
List down five human chromosomal aberrations. Give the corresponding karyotype for each type then briefly describe the traits of affected individuals.
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Related Questions
- genetics question for Icke P. Jenny, like her mother, is heterozygous for both X-linked traits. Her father suffered from bothhypophosphatemia and muscular dystrophy. Jenny’s fiancé, Mark has a mother suffering from musculardystrophy despite having normal bone conditions. His father has been blessed with strong bones andmuscles but suffered from amelogenesis imperfecta. a. Give the complete genotypes of the following individuals: Jenny, Jenny's mother, Jenny's father, Mark, Mark's mother, Mark's father. b. Should Jenny and Mark eventually marry, what is the probability that they will have: a child with muscular dystrophy, a child with amelogenesis imperfecta, a son with hypophosphatemia, a daughter with muscular dystrophy, a child with the same genotype as Jenny, a child with the same genotype as Markarrow_forward17. In rats, the following genotypes of two independently assorting autosomal genes determine coat color.A_B_ (gray)A_bb (yellow)aaB_ (black)aabb (cream)A third gene pair on a separate autosome determines whether or not any color will be produced.The CC and Cc genotypes allow color according to the expression of the A and B alleles.However, the cc genotype results in albino rats regardless of the A and B alleles present. Given the inheritance pattern of coat color in rats described in Problem 17, predict the genotype and phenotype of the parents who produced the following offspring: (c) 27/64 gray: 16/64 albino: 9/64 yellow: 9/64 black: 3/64 creamarrow_forward10) Phenylketonuria (PKU) is a recessive disorder. Jack and Jane look normal but have a child with PKU. Therefore, what are the genotypes of Jack and Jane? __________________________________arrow_forward
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