M3.1 Laboratory Report 3- Zhiyuan Wu.docx

M3.1 Laboratory Report 3 Name: Zhiyuan Wu Date: 1/29/2024 Propose: Use a computer simulation to investigate what projectile motion is. Introduction: Kinematics equations ， gravitational acceleration Procedure: Use a computer simulation, input angle, initial speed and so on. Then see the vectors of acceleration. Data and Data Evaluation: Part 1 Pumpkin: Initial Speed Time Range Height 2 m/s 1.28 s 2.55 m 0 m 4 m/s 1.28 s 5.11 m 0 m 6 m/s 1.28 s 7.66 m 0 m 8 m/s 1.28 s 10.22 m 0 m 10 m/s 1.28 s 12.77 m 0 m 12 m/s 1.28 s 15.33 m 0 m 14 m/s 1.28 s 17.88 m 0 m 16 m/s 1.28 s 20.43 m 0 m 18 m/s 1.28 s 22.99 m 0 m 20 m/s 1.28 s 25.54 m 0 m These values show with the increase of initial speed, the range is increasing, but the time of landing is not change. Car: Initial Speed Time Range Height 2 m/s 1.28 s 2.55 m 0 m 4 m/s 1.28 s 5.11 m 0 m 6 m/s 1.28 s 7.66 m 0 m 8 m/s 1.28 s 10.22 m 0 m 10 m/s 1.28 s 12.77 m 0 m

12 m/s 1.28 s 15.33 m 0 m 14 m/s 1.28 s 17.88 m 0 m 16 m/s 1.28 s 20.43 m 0 m 18 m/s 1.28 s 22.99 m 0 m 20 m/s 1.28 s 25.54 m 0 m Comparing the two results, I find with the same initial speed, whatever the object is, the time to landing and range will not change. Part 2 investigating gravitational acceleration The direction of the vector is down, and it represents gravitational acceleration. The length of the vector doesn’t change throughout its flight. It can tell me the direction and magnitude of the acceleration acting on the cannonball throughout its duration of flight. If we change the angle of the cannon, I think the acceleration vector will not change, because the gravitational acceleration is constant. The acceleration vector does not change its length and direction at new angle, my prediction is right. Discovery: The launch angle affects the trajectory and range of the projectile but does not affect the gravitational acceleration acting on it.

investigating velocity Angle 45 degree: The length of the velocity vector in the y-direction decreases as the cannonball rises, becomes zero at the peak of its trajectory, and then increases as the cannonball falls back down. Initially upward, it becomes zero at the peak, and then downwards as the cannonball descends. The velocity vector in the y-direction becomes zero at the peak of the trajectory. This is the highest point of the flight, where the cannonball momentarily has no vertical motion. Ascent: On leaving the cannon, the vertical component of velocity is maximum and positive. It decreases due to gravity. Peak: At the peak, all the upward velocity is counteracted by gravity, making the vertical velocity zero. Descent: After the peak, the cannonball gains downward velocity, increasing in magnitude until it hits the ground. The velocity in the x-direction remains constant throughout the flight.

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